On a graph, the point moves down 9 points and to the right by 2
Hello there!
9/10 < 11/12
11/12 is bigger then 9/10. I know this because, 11 is bigger then nine and 12 is bigger then.
Answer:
Step-by-step explanation:
1) Solve the equation: [4ax - (a + b)](a + b) = 0, where a and b are constants.
- if a + b = 0, then x has infinitely many solutions
or
- 4ax = a + b
- x = (a + b)/4a, a≠0
2) Solve the equation m²x + 1 = m(x + 1), where m is a parameter.
- m²x + 1 - mx - m = 0
- (m²- m)x = m - 1
- m(m - 1)x = m - 1
- mx = 1
- x = 1/m, m≠0
3) Given that the equation a(2x - 1) = 3x - 3 has no solution, find the value of the parameter a.
- a(2x - 1) = 3x - 3
- 2ax - a = 3x - 3
- 2ax - 3x = a - 3
- (2a - 3)x = a - 3
- x = (a - 3)/(2a - 3)
<u>The equation has no solution if:</u>
Answer:
Interpreting as: X=a-sqrt b X=a+sqrt b
Input:
X = a - sqrt(b) X = a + sqrt(b)
Alternate forms:
{a = (sqrt(b) + 1) X, a = X - sqrt(b), b = 0 ∨ X = -1}
{a = (sqrt(b) + 1) X, a + sqrt(b) = X, sqrt(b) (X + 1) = 0}
To find the correct option we need to calculate each of the given options.
Option (1):

Option (2):

Option (3):

option (4)
So, the correct answer is option (2)