Question

Find the error (-8x^2y^2)^2= -64x^4y^4

Answer 1

Answer:

64 shouldnt be negative anymore

Step-by-step explanation:

(-8x^2y^2)^2 = -64x^4y^4

when exapnding the left side it would be...

(-8x^2y^2)^2

Apply exponent rule (-a)^n = a^n

→ (8x^2y^2)^2  

→ (8^2)(x^2)^2

→ (8^2) = 64

→ 64(x^2)^2 = 64x^4

Hope this helps. Let me know if you have any questions !

Have a nice rest of you day :)

Answer 2

Answer:

$(-8)^2\neq-64$

Step-by-step explanation:

Using the distributive property to expand, we have

$(-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.$

Squaring each term, we have

$(-8x^2y^2)^2=64x^4y^4.$

The mistake was that $8^2=64,$ not $-64.$ Using the fact that $8^2=64,$ the right answer would be

$\boxed{64x^4y^4}$.