Answer:
2
Step-by-step explanation:
<u>Given AP where:</u>
<u>To find</u>
<u>Since</u>
- a₄ = a₁ + 3d
- a₂ = a₁ + d
- a₆ = a₁ + 5d
<u>Initial equations will change as:</u>
- a₁ + 3d = 2(a₁ + d) - 1 ⇒ a₁ + 3d = 2a₁ + 2d - 1 ⇒ a₁ = d + 1
- a₁ + 5d = 7 ⇒ a₁ = 7 - 5d
<u>Comparing the above:</u>
- d + 1 = 7 - 5d
- 6d = 6
- d = 1
<u>Then:</u>
- a₁ = d + 1 = 1 + 1 = 2
- a₁ = 2
The first term is 2
A line that would appear like this ( / ) on a graph would have a positive slope because the coordinates that the line passes through are increasing from left to right.
Answer: The p(success) = 0.6
Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.
If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.
That is 0.48 + 0.16 = 0.64
Rounding our answer to one decimal place gives us 0.6.

by using the integration formula
we get,

now put the value of t=\sin\theta in the above equation
we get,

hence proved
Answer:
x=7, x= -2
Step-by-step explanation:
- Start by putting the whole equation to one side: x2-5x=14 ----> x2-5x-14=0
- Next, factor the equation: x,x -7,2 ----> (x-7)(x+2)=0
- Now, solve both equations: x-7=0....x=7 AND x+2=0.....x= -2
- Plug both in to make sure that they are correct....both are correct