This is asking how many ways can we choose 13 songs from a set of 25.
The formula is:
n! / r! * (n -r)! =
25! / 13! * 12! which equals
25 *24 *23 *22 *21 *20 *19 *18 *17 *16 *15 *14 *13! divided by
13! * 12! which equals
25 *24 *23 *22 *21 *20 *19 *18 *17 *16 *15 *14 divided by
12* 11* 10* 9* 8* 7* 6* 5* 4* 3* 2*
which equals
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2,490,952,020,480,000
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</span>
divided by
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479,001,600
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</span>
</span>
and that equals
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5,200,300
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</span>
combinations
Here's a combination calculator to check your work:
http://www.1728.org/combinat.htm
1) the types of number are the negative integers (e.g √-1 √-3 <span>√-5 are not defined)
2) the answer is No, proof: 2x</span>√-1 is not defined because <span>√-1 doesn't exist
3) the answer is No, proof: </span>√-1 - 3 is not defined because √-1 doesn't exist
4) the answer is Yes, proof: (√-1 )²= -1 this is a real number
5) the answer is No, proof: (√-1 )^3= (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist
6) the result would be defined with the following cases:
√-1+n, n>1
√-1xn, n<0
√-1/n, n<0
7) the result would not be defined with the following cases:
√-1+n, n<0
√-1xn, n>0
√-1/n, n>0
8) to square <span>3 + √-1, I use the method of complex number
i²= -1, it implies i= </span>√-1
so 3+√-1=3+i, and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1
9) it is used for finding complex roots of a number
B. (n + 15) x 3--- That seems to be the correct answer. I hope I helped!
(-5x^5)(a) = 25x^7 + 100x^5
<u>+5x^5 +5x^5</u>
a = 25x^7
Answer:
Password for the 1hdhhdhfhdhrhehjfujdjwjwjdjhf
Step-by-step explanation:
