3 years ago

A rectangle has a length that is twice the meaure of its width. Perimeter is 54. What is the area

1 answer:

5 0

L = 2W
P = 2L + 2W
Plug 2W in for L.
54 = 2(2W) + 2W
54 = 4W + 2W
54 = 6W
Divide both sides by 6
W = 9
L = 2* 9
L = 18
A = L * W
A = 9 * 18
A = 162 units^2

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