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denis-greek [22]
2 years ago
8

As with simple linear regression, we desire the residuals to (select all that apply) have large variance. have constant variance

. have a mean close to 1. have a mean close to 0. have in increasing mean.
Mathematics
1 answer:
dimulka [17.4K]2 years ago
5 0

As with simple linear regression, we desire the residuals to:

  • Have constant variance.
  • Have a mean close to 0.

<h3>What is a simple linear regression?</h3>

It should be noted that a simple linear regression simply means a model that describes the relationship between a dependent variable and an independent variable.

In this case, as with simple linear regression, we desire the residuals to have constant variance and have a mean close to 0.

Learn more about regression on:

brainly.com/question/25987747

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A sequence is defined by the function f(n)=f(n-1)+5. Where n represents the number of the term for n&gt;1 and f(1)=-4. What are
Neporo4naja [7]

Answer:

The first four terms of the above sequence are 1, 6, 11, 16.

Step-by-step explanation:

A sequence is defined by the function f(n)=f(n-1)+5.

Where n represents the number of the term for n>1

First Put n = 2

f(2)=f(2-1)+5.

    = f (1) + 5

    = -4 + 5

    = 1

Second Put n = 3

f(3)=f(3-1)+5.

    = f (2) + 5

    = 1 + 5

    = 6

Third Put n = 4

f(4)=f(4-1)+5.

    = f (3) + 5

    =  6+ 5

    = 11

Second Put n = 5

f(5)=f(5-1)+5.

    = f (4) + 5

    = 11 + 5

    = 16

Therefore the first four terms of the above sequence are 1, 6, 11, 16.

3 0
3 years ago
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Your company is hosting a benefit 5 kilometer race. How long will the race be to the nearest tenth of a mile?
Akimi4 [234]
1km=0.62 miles

so multiply 1km by 5 to get 5km
multiply 0.62 by 5 to get km to miles
0.62 times 5=3.1

answe ris 3.1 miles
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3 years ago
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If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)
Elina [12.6K]

If we write k where we see x in the equation and set the result equal to -10, we get the result.

  • f(k)=k(k)^3+k^2-k(k)+2
  • =k^4+k^2-k^2+2
  • =k^4+2=-10
  • k^4=-12
  • k_{1}=\sqrt[4]{3}(-1-i)
  • k_{2}=\sqrt[4]{3}(-1+i)
  • k_{3}=\sqrt[4]{3}(1-i)
  • k_{4}=\sqrt[4]{3}(1+i)

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1 year ago
8^−2xa^7 simplified math assignment
Delvig [45]
Uh I don’t understand
5 0
3 years ago
2y = x + 3 5y = x - 7 What is the solution set of the given system?
prohojiy [21]
<span>2y = x + 3 then x = 2y - 3
5y = x - 7 then x = 5y + 7

so 
</span>2y - 3 = 5y + 7
2y - 5y = 7 + 3
-3y = 10
y = -10/3
y = -3 1/3

<span>2y = x + 3
</span>2 (-10/3) = x + 3
-20/3 - 3 =x
-29/3 = x
-9 2/3 =x
or
x = -9 2/3

solutions: x = -9 2/3 and y = -3 1/3

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