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3 years ago

What is reasonable first step that can be used to solve the equation 2(x+6)=3(x-4)+5?

Mathematics

1 answer:

blagie [28]3 years ago

8 0

Answer:

Distribute 2 to (x + 6) and 3 to (x-4)

Step-by-step explanation:

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(Law of Sines)

Mariana [72]

Answer:

Option (D) is correct.

Step-by-step explanation:

In a triangle BCD , with b, c, d as the sides of triangle.

Sine rule states when we we divide side b by the sine of angle B then it is equal to side c divided by the sine of angle C and also equal to side d divided by the sine of angle D.

Using Sine rule,

$\frac{b}{\sin B}=\frac{c}{\sin C}=\frac{d}{\sin D}$

Consider the first and third ratio,

$\frac{b}{\sin B}=\frac{d}{\sin D}$

Substitute the values of d = 3 , b= 5 and ∠D=25°

$\Rightarrow \frac{5}{\sin B}=\frac{3}{\sin 25^{\circ}}$

$\Rightarrow \sin B=\frac{\sin 25^{\circ} \times 5}{3}}$

$\Rightarrow \sin B=45,135$

Thus, Measure of angle B is 45 and 135 as sinB is positive is first and 2nd quadrant.

Thus, option (D) is correct.

7 0

3 years ago

Read 2 more answers

Solve by elimination:<br> 4x+9y=28<br> -4x-y=-28

nikdorinn [45]

Step-by-step explanation:

4x+9y=28

-4x-y=-28

8y=0

divide both side by 8

y=0

solve for X in equation 1

4(X)-9(0)=28

4x-0=28

4x =28

divide both side by 4

4x/4=28/4

X= 7

y=0,x=7

4 0

3 years ago

What is the measure of angle B in the triangle?

Marat540 [252]

$180 - 120 = 60 \\ 60 - 16 = 44 \\ 44 \div 2 = 22$
x is 22
hope this helps

8 0

3 years ago

Read 2 more answers

Math plz help it's hard (8th grade math)

Mrac [35]

This is what I got I dont know if It should be an equation but that's all i can get to, gl

8 0

3 years ago

Read 2 more answers

Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9

a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is $x^2+4x-21=0$ . We need to find the solution of this equation.

If the equation is in the form of $ax^2+bx+c=0$ , then its solutions are given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

$x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7$

So, the solutions of the quadratic equation are 3 and -7.

6 0

3 years ago