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3 years ago

Solve for x in this equation:3/4+|5-x|=13/4

2 answers:

7 0

Well, anything in absolute value lines become positive, so the equation would be:

3/4+5+x=13/4

Next we subtract 3/4 to both sides to start separating the variable (x).

So, 5+x=10/4

Next, we subtract 5 from both sides. (5= 20/4)

And we get: x=-10/4.

I hope this helps!

ra1l [238]3 years ago

6 0

Answer:

Step 1: Isolate the absolute value by subtracting 3/4 from both sides of the equation.

Step 2: Represent the negative case by rewriting the absolute value equation as: 5 - x = - 5/2 

Step 3: Represent the positive case by rewriting the absolute value equation as 5 - x = 5/2 * v

Step 4: Isolate the variable term by subtracting this value from both sides of the negative case equation : 5

Step 5: Solve the positive case equation. x = 5/2

i got it right on ed2020

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ivolga24 [154]

Answer:

His goal was 93.75 miles

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3 years ago

Scateboard cost Rs450each in my local store,The shop keeper says if I buy 1 I can buyanother for only 7/9 of the normal price,ho

Whitepunk [10]

Answer:

the cost will be Rs 350

Step-by-step explanation:

The Scateboard cost Rs 450 each in the local store,The shop keeper says if I buy 1 I can buy another for only $\frac{7}{9}$ of the normal price. We are asked to determine the cost of a second scateboard .

Hence the cost will be $\frac{7}{9}$ of the normal cost that is

$\frac{7}{9} \times 450$

$7 \times 50$

$350$

the cost will be Rs 350

6 0

3 years ago

Answer correct and fast

inna [77]

Hello there I hope you are having an great Day :)

1) 32780ml = 32.78

2) 37 1/2% of 24 = 9

Hopefully that helps you :)

3 0

3 years ago

Solve the system of linear equations using multiplication.

Anna71 [15]

Answer:

$(8,-1)$

Step-by-step explanation:

The given system is:

$3x+3y=21$

$6x+12y=36$

Since I prefer to use smaller numbers I'm going to divide both sides of the first equation by 3 and both sides of the equation equation by 6.

This gives me the system:

$x+y=7$

$x+2y=6$

We could solve the first equation for $x$ and replace the second $x$ with that.

Let's do that.

$x+y=7$

Subtract $y$ on both sides:

$x=7-y$

So we are replacing the second $x$ in the second equation with $(7-y)$ which gives us:

$(7-y)+2y=6$

$7-y+2y=6$

$7+y=6$

$y=6-7$

$y=-1$

Now recall the first equation we arranged so that $x$ was the subject. I'm referring to $x=7-y$ .

We can now find $x$ given that $y=-1$ using the equation $x=7-y$ .

Let's do that.

$x=7-y$ with $y=-1$ :

$x=7-(-1)$

$x=7+1$

$x=8$

So the solution is (8,-1).

We can check this point by plugging it into both equations.

If both equations render true for that point, then we have verify the solution.

Let's try it.

$3x+3y=21$ with $(x,y)=(8,-1)$ :

$3(8)+3(-1)=21$

$24+(-3)=21$

$21=21$ is a true equation so the "solution" looks promising still.

$6x+12y=36$ with $(x,y)=(8,-1)$ :

$6(8)+12(-1)=36$

$48+(-12)=36$

$36=36$ is also true so the solution has been verified since both equations render true for that point.

5 0

3 years ago

Read 2 more answers

Should the quotient of an integer divided by a nonzero integer always be a rational number? Why or Why not?

lubasha [3.4K]

Yes, it will always be a rational number. I'll expound on this by defining what a rational number is. It is any number that can be expressed as a fraction. Otherwise, it is called an irrational number with a non-terminating decimal expansion. So, although 1/3 has a non-terminating decimal expansion because it is equal to 0.33333333...., it is still a rational number because it can be expressed into a fraction.

8 0

3 years ago