Calculate the mode 5,10,12,4,6,11,13,5 show work

1 answer:

7 0

The answer for this question is 5 because 5 shows up the most. The mode is the number that shows up more often then any other numbers

You might be interested in

Y=x^2+12x+35 into the form y=(x-h)^2+k

LiRa [457]

Answer:

y = (x + 6)² - 1

Step-by-step explanation:

So there are two ways of doing it, completing the square or partial factoring (which is what i prefer and will show)

so we will get x first:

x^2+12x

We are factoring x

x(x+12)

Now you do x=-12/2

x=-6

Now that you have x, you plg that back into the equation to get y

y= -6^2 +12(-6) +35

= 36-36+35

=-1

Put into vertex form

y = (x + 6)² - 1

4 0

2 years ago

HELP HELP HELP HELP HELP HELP

ANTONII [103]

Answer:

57mm

Step-by-step explanation:

C=2(pi)(r)

C=2(3.14)(9)

C=56.52

rounding up, its 57mm

6 0

3 years ago

A lottery game requires that a person select in uppercase or lowercase letter followed by two different two-digit numbers (where

Irina-Kira [14]

Using the Fundamental Counting Theorem, it is found that there are 416,520 ways to fill out a lottery ticket.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with $n_1, n_2, \cdots, n_n$ ways to be done, each thing independent of the other, the number of ways they can be done is:

$N = n_1 \times n_2 \times \cdots \times n_n$

In this problem:

First, one uppercase or lowercase letter is chosen, there are 26 of each, hence $n_1 = 52$ .

Then, two different two-digit numbers are chosen, and there are 90 of them, hence $n_2 = 90, n_3 = 89$ , as the third digit has to be different of the second.