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sdas [7]
4 years ago
8

Calculate the mode 5,10,12,4,6,11,13,5 show work

Mathematics
1 answer:
yaroslaw [1]4 years ago
7 0
The answer for this question is 5 because 5 shows up the most.  The mode is the number that shows up more often then any other numbers
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HELP ME!!!!!!!!!!!!!!!
Katen [24]
Last answer is right
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3 years ago
A rectangle has an area of 24cm, how long could the sides of the rectangle be? Give 3 examples,
Flura [38]
1. 12cm long and 2cm wide

2. 8cm long and 3cm wide

3. 6cm long and 4cm wide

3 0
4 years ago
Mary wants to put 1/10 of a kilogram of bird seed in each of the bird cages in her pet shop. She has 3/10 of a kilogram of bird
alex41 [277]

Answer:

  A)  3

Step-by-step explanation:

If you simply look at the given numbers, it should be pretty clear that 3 tenths is 3 times 1 tenth.

When Mary puts 1/10 kg in each cage, she can do that for 3 cages with 3/10 kg of bird seed.

__

If you let c represent the number of cages, then the amount of bird seed used will be (1/10)c. This will be equal to the amount available when we use it all for filling cages:

  (1/10)c = (3/10)

Multiply both sides of the equation by 10:

  c = 3

Mary can fill 3 cages with available seed.

5 0
4 years ago
Which function is the inverse of f(x) = 2x + 32?
kogti [31]

Answer:

(x/2)-16=f( x)

Step-by-step explanation:

f( x)=2x+32

y=2x+32

inve.rse (switc.h x an.d y)

x=2y+32

subtr.act 32 on eac.h sid.e

x-32=2y

divid.e ea.ch s.ide b.y 2

(x-32)/2=(2y)/2

(x/2)-16=y

rev.ise y a.s f( x)

(x/2)-16=f( x)

So.me wo.rd is sup.posedly ba.d an.d I do.n't kn.ow wha.t s.o I pu.t ra.ndom per.iods eve.rywhere.

7 0
4 years ago
What is the value of (Negative 14 Superscript 0 Baseline) Superscript negative 2? Negative StartFraction 1 Over 196 EndFraction
Nookie1986 [14]

Answer:

1

Step-by-step explanation:

Assuming, we want to find the value of ((-14)^0)^{-2}

Recall that: any non-zero number exponent zero is 1.

Using this property, we simplify our expression to (1)^{-2} since (-14)^0=1

Now using the property of exponents: a^{-n}=\frac{1}{a^n}

This implies that:1^{-1}=\frac{1}{1^2}=\frac{1}{1}=1

The correct answer is 1

5 0
4 years ago
Read 2 more answers
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