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Aloiza [94]
3 years ago
15

Given that √3^n = 3^x/27^y. Express n in terms of x and y.

Mathematics
1 answer:
Radda [10]3 years ago
7 0

Answer:

Step-by-step explanation:

HEllo,

(\sqrt{3})^n=3^{\frac{n}{2}}=\dfrac{3^x}{27^y}=3^x\times(3^3)^{-y}=3^{x-3y}\\\\\dfrac{n}{2}=x-3y\\\\\boxed{\sf \bf n= 2x-6y}

Hope this helps

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Given the sequence 8, 16, 32, 64, ..., which expression would give the thirteenth term?
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8, 16, 32, 64,…
 ×2  ×2  ×2

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a_{n} = 8 * 2^{13 - 1}
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           First Term: 8
      Second Term: 16
          Third Term: 32
        Fourth Term: 64
           Fifth Term: 128
          Sixth Term: 256
     Seventh Term: 512
       Eighth Term: 1024
         Ninth Term: 2048
        Tenth Term: 4096
   Eleventh Term: 8192
     Twelfth Term: 16384
Thirteenth Term: 32768

The\ expression\ that\ would\ give\ the\ thirteenth\ term\ of\ the\ problem\ would\ be\ the\ equation\ of\ the\ geometric\ sequence,\ which\ is\ equal\ to\ a_{n} = a_{1} * r^{n - 1}.

5 0
3 years ago
Read 2 more answers
Please help ASAP! It’s due in 20 min and I have complete it! I just need the statements and reasons! Thank you
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Answer:

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Step-by-step explanation:

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L = W + 3
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