Question

Can anyone please solve this for me right now?

Answer 1

The width of the path when the length of the outer rectangle is 26+2x and width of it is 18+2x is 4 meters.

What is the area of a rectangle?

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

A=a×b

Here, (a)is the length of the rectangle and (b) is the width of the rectangle

The length of the outer rectangle is 26+2x and width of it is 18+2x. The area of this rectangle is 884² m. Thus,

A=a×b

884=(26+2x)×(18+2x)

884=468+52x+36x+4x²

4x²+88x-416=0

Divide both side with 4,

x²+22x-104=0

x²+26x-4x-104=0

x(x+26)-4(x+26)=0

(x+26)(x-4)=0

x=-26,4

Take the positive value 4. The width of the path is equal to x which is 4 meters.

Hence, the width of the path when the length of the outer rectangle is 26+2x and width of it is 18+2x is 4 meters.

Learn more about the area of rectangle here;

brainly.com/question/11202023

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