Question

What is the standard form of this function? F(x) = -(x-4)^2 + 2

Answer 1

Answer:

f (x) = -2 (x + 6)^2 + 2

Step-by-step explanation:

f (x) = -2x^2 - 24x - 70 <--- divide out -2 out of the first two terms...

f (x) = -2 (x^2 + 12x) - 70 <-- divide the x coefficient by 2 and then square it, then add AND subtract it)  

f (x) = -2 (x^2 + 12x + (12/2)^2 - (12/2)^2) - 70  

f (x) = -2 (x^2 + 12x + 36 - 36) - 70 <--- distribute the -2 onto -36 to get it out of the brackets..  

f (x) = -2 (x^2 + 12x + 36) + 72 - 70 <-- combine constants and factor perfect square trinomial...  

f (x) = -2 (x + 6)^2 + 2 <-- standard form...

Answer 2

Answer: f(x) = -x^2 + 8x − 14

Step-by-step explanation:

just took the test.