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tekilochka [14]
3 years ago
14

Solve the inequality. Graph the solution. Describe the graph in the area provided. Be sure to indicate where there is an open or

closed circle and what direction the number line is shaded in.

Mathematics
1 answer:
valkas [14]3 years ago
8 0

To solve this problem, we can to simply plot using a graphing tool and the region under the area would be given. We would see there's no solution for this compound inequality

<h3>Graphing of Inequality</h3>

The given inequalities in this question are

  • x + 4 > 0.01
  • 32 ≤ - 4x

When we plot this, we would see that no solution exists for this compound inequality problem.

Kindly check the attach image for more details.

Learn more on graphing of inequality here;

brainly.com/question/11234618

#SPJ1

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Arada [10]
I think that it's 111
4 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
At oceanside middle school 110 students tried out for the football team only 80% of the students that tryout make the team how m
Olenka [21]

Step-by-step explanation:

answer is 22 students in the team

<em>how </em><em>do </em><em>u </em><em>get </em><em>it? </em>

you know it is 80% of the students went for try out so you do 100% - 80% give you 20% students the number of students in the team already. so you do 20 / 100 x 110 students which already in the whole school over 1 which would give it 22

3 0
3 years ago
Helpppppppppppp meeee​
nikklg [1K]

Answer:

25z^{4} + 30z³ + 29z² + 12z + 4

Step-by-step explanation:

(5z² + 3z + 2)²

= (5z² + 3z + 2)(5z² + 3z + 2)

Each term in the second factor is multiplied by each term in the first factor, that is

5z²(5z² + 3z + 2) + 3z(5z² + 3z + 2) + 2(5z² + 3z + 2) ← distribute parenthesis

= 25z^{4} + 15z³ + 10z² + 15z³ + 9z² + 6z + 10z² + 6z + 4 ← collect like terms

= 25z^{4} + 30z³ + 29z² + 12z + 4

4 0
2 years ago
Anybody can help me ?
erica [24]

Answer:

R/Z

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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