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marshall27 [118]
3 years ago
13

PLEASE HELP: The slope of the line below is 2. Use the coordinates of the labeled point to find a point-slope equation of the li

ne.

Mathematics
2 answers:
e-lub [12.9K]3 years ago
5 0
The answer is c! :):):)
alex41 [277]3 years ago
4 0

Answer:

A: y-9 =2(x-1)

Step-by-step explanation:


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<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%20%7B%7D%5E%7B2%7D%20%20-%205" id="TexFormula1" title="f(x) = x {}^{2} - 5
faust18 [17]

Answer:

The vertex is (0, -5) and the axis of symmetry is x = 0.

Step-by-step explanation:

In order to find the axis of symmetry, we look for the x value of the vertex. We can find this using the equation -b/2a, in which a is equal to the coefficient of the x^2 term and b is the coefficient of the x term.

x = -b/2a

x = 0/2(1)

x = 0/2

x = 0

So the axis of symmetry is 0 as is the x value of the vertex. Now we can find the y value by plugging in the x value into the equation.

f(x) = x^2 - 5

f(x) = 0^2 - 5

f(x) = 0 -5

f(x) = -5

This gives us a vertex of (0,-5)

7 0
3 years ago
Today, 6 friends went out for lunch. Their total bill was $50.41 , including tax and gratuity. One of them ordered only soda and
Burka [1]

Answer:

50.41 minus 1.71 is 48.70 divided by 5 is 9.74

3 0
3 years ago
(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot
VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

a)

We could model this situation with a binomial distribution

P(6;k)=\binom{6}{k}p^kq^{6-k}

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

So

\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}

b)  

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}

P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281

P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484

P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438

P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109

P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781

and adding up these values we have that the probability that Y is less than 6 is

\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%

c)

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.  

In a binomial distribution, the standard deviation is  

s = \sqrt{npq}

In this case  

\sqrt{200(0.85)(0.15)}=5.05

<em>Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05</em>

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is  

0.0238 or 2.38%

d)<em> In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).</em>

In general, we can do this if the sample of size n the following inequalities hold:

np\geq 5 \;and\;nq \geq 5

in our case np = 200*0.85 = 170 and nq = 200*0.15 = 30

4 0
3 years ago
Bonsoir pour vais vous m'aider svp développer et réduire l'expression D=(2x+3)²-(x+4)² et factoriser D Svp aider moi
GalinKa [24]

Answer:

d = 3x²+ 4x - 7

C'est la réponse j'espère que ça aide.

5 0
3 years ago
PLEASE HELP!<br> IMAGE DOWN BELOW!
ankoles [38]

Answer:

1. 11t

2.7w+28

3. 2c+11

4. 8n

5. 10r+15

6. 24−8g

7. 17d−9

8. 8g+7z

9. 23b

10. 2rs+1

11. 9f+9g

12. 4x+y

13. 21a+14

14. 21a+14

15. 6−3k

16. 18n+36

17. 9s+3t

18. 8a−12b

19. 11m+n

20. 2+6z

21. 8x+6y

22. 7hg−7

23. 4st+5

24. 2r+17

25. 7w+6

26. 3(c+2)

27. 8f−4g

28. 2+8q+3r

Step-by-step explanation:

there you go, sorry it took so long

6 0
3 years ago
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