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Ivahew [28]
3 years ago
10

If an atom’s mass number is 210 and its atomic number is 85, how many neutrons does it have?

Chemistry
1 answer:
Nadya [2.5K]3 years ago
3 0
Mass number is the total number of Protons and Neutrons. Simply subtract 85 from 210. 210-85=125 neutrons
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A scientist measures the standard enthalpy change for the following reaction to be 81.1 kJ :2CO2(g) + 5 H2(g)C2H2(g) + 4 H2O(g)B
posledela

<u>Answer:</u> The enthalpy of the formation of CO_2(g) is coming out to be -410.8 kJ/mol.Z

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

For the given chemical reaction:

2CO_2(g)+5H_2(g)\rightarrow C_2H_2(g)+4H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(C_2H_2(g))})+(4\times \Delta H^o_f_{(H_2O(g))})]-[(2\times \Delta H^o_f_{(CO_2(g))})+(5\times \Delta H^o_f_{(H_2(g))})]

We are given:

\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(H_2(g))}=0kJ/mol\\\Delta H^o_f_{(C_2H_2(g))}=226.7kJ/mol\\\Delta H^o_{rxn}=81.1kJ

Putting values in above equation, we get:

81.1=[(1\times (226.7)})+(4\times (-241.8))]-[(2\times \Delta H^o_f_{(CO_2(g))})+(5\times (0))]\\\\\Delta H^o_f_{(CO_2(g))}=-410.8kJ/mol

Hence, the enthalpy of the formation of CO_2(g) is coming out to be -410.8 kJ/mol.

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If the temperature becomes higher than room temperature (25 degrees), we can now conclude that the reaction is exothermic and heat was indeed given out during the course of the reaction.

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Topographic maps generally shows Natural features such as Rivers and Lakes.

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