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Nadya [2.5K]
3 years ago
14

A car with a mass of 3,500lbs accelerates negatively from 35m/s to 8m/s in 8s. What is the

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

a=-3.37\ m/s^2

Explanation:

Given that,

A car accelerates negatively from 35m/s to 8m/s in 8s.

We need to find the car's acceleration.

Initial speed, u = 35 m/s

Final speed, v = 8 m/s

Time, t = 8 s

The acceleration of an object is equal to the rate of change of velocity. So,

a=\dfrac{v-u}{t}

Put all the values,

a=\dfrac{8-35}{8}\\\\a=-3.37\ m/s^2

So, the acceleration of the car is equal to -3.37\ m/s^2.

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Answer- 33.4 kJ


Explanation-

100 g H2O x (1mol/18g) = 5.5 mol

q=(5.5 mol)(6.01 KJ/mol)= 33.4 kJ
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3 years ago
Magnesium burns with a very bright light. When the flame goes out, a White powder is left behind. what is the word equation for
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When magnesium is burned, it reacts with oxygen in air not with the fire. The fire is the energy needed for the reaction to happen. Magnesium reacts with oxygen forming magnesium oxide. The light emitted from the reaction is because the reaction produced a lot of heat.
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3 years ago
Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0
olya-2409 [2.1K]

Answer:

pH=-1.37

Explanation:

We are given that 25 mL of 0.10 M CH_3COOH is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of CH_3COOH=25mL=0.025 L

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL=\frac{35}{1000}=0.035 L

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of CH_3COOH=0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+=0.10\times 0.025=0.0025 moles

Number of moles of OH^-=0.10\times 0.01=0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+=\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L

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pH=-1.37

6 0
3 years ago
. What is a carbonyl group? Draw the carbonyl groups that are characteristic of aldehydes, ketones, carboxylic acids, and esters
Elan Coil [88]

Answer :

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Carboxylic group : It is the class of organic compound in which the carboxylic (-COOH) group is attached to a hydrocarbon is known as carboxylic.

The general formula of carboxylic is, C_nH_{2n+1}COOH. According to the IUPAC naming, the carboxylic are named as alkanoic acids.

Aldehyde group : It is the class of organic compound in which the (-CHO) group is attached to a hydrocarbon is known as aldehyde.

The general representation of aldehyde is, R-CHO. According to the IUPAC naming, the aldehyde are named as alkanals.

Ketone group : It is the class of organic compound in which the (-CO) group is directly attached to the two alkyl group of carbon is known as ketone.

The general representation of ketone is, R-CO-R^'. According to the IUPAC naming, the ketone are named as alkanone.

Ester group : It is the class of organic compound in which the (-COO) group is directly attached to the two alkyl group of carbon is known as ester.

The general representation of ester is, R-COO-R^'. According to the IUPAC naming, the ester are named as alkyl alkanoate.

6 0
3 years ago
Sarah is in her chemistry lab doing an experiment. When she goes to take the mass of the chemical she is working with, she disco
cupoosta [38]

Answer:

10 x 5 = 50

Explanation:

50 is the mass of her chemical.

7 0
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