Question

The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon

Answer 1

Answer:

$\boxed{\text{300 g}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:         32                          60

           CH₃OH + CO ⟶ CH₃COOH

m/g:        160

(a) Moles of CH₃OH

$\text{Moles of CH _{3} OH} = \text{160 g CH _{3} OH }\times \dfrac{\text{1 mol CH _{3} OH }}{\text{32 g CH _{3} OH}}= \text{5.00 mol CH _{3} OH}$

(b) Moles of CH₃COOH

$\text{Moles of CH _{3} COOH} = \text{5.00 mol CH _{3} OH } \times \dfrac{\text{1 mol CH _{3} COOH}}{\text{1 mol CH _{3} OH }} = \text{5.00 mol CH _{3} COOH}$

(c) Mass of CH₃COOH

$\text{Mass of CH _{3} COOH} =\text{5.00 mol CH _{3} COOH} \times \dfrac{\text{60 g CH _{3} COOH}}{\text{1 mol CH _{3} COOH}} = \textbf{300 g CH _{3} COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is \boxed{\textbf{300 g}} }$