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Alex777 [14]
3 years ago
13

Radius= 4cm. find the area and diameter of the circle​

Mathematics
2 answers:
Bezzdna [24]3 years ago
6 0
<h3>given:</h3>

radius= 4 cm

<h3>to find:</h3>

the area and the diameter of the circle.

<h3>solution:</h3><h3>diameter:</h3>

d = 2r

d = 2 \times 4

d = 8 \: cm

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>diameter</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circle</u><u> </u><u>is</u><u> </u><u>8</u><u> </u><u>centimeters</u><u>.</u>

<h3>area:</h3>

a = \pi {r}^{2}

a = \pi \times  {4}^{2}

a = 50.26548 \:  {cm}^{2}

a = 50.27 \:  {cm}^{2}

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circle</u><u> </u><u>is</u><u> </u><u>50.27</u><u> </u><u>square</u><u> </u><u>centimeters</u><u>.</u>

antiseptic1488 [7]3 years ago
5 0
<h3>Given:</h3>
  • Radius= 4 centimeters
<h3>Diameter of the circle:</h3>

diameter = 2r

d = 2 \times 4

d = 8 \: cm

<h3>Area of the circle:</h3>

area = \pi {r}^{2}

a = \pi \times  {4}^{2}

a = 50.26548 \:  {cm}^{2}

a = 50.27 \:  {cm}^{2}  \: (2 \: d.p)

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3 years ago
1. N - 80 = 40 2. 15n = 30 3. N + 284 = 350 4. 6 + 9 = 3 x n 5. N divided by 3 = 6 +1 6. 12 - 8 = n divided by 5 7. 58 x 6 = n -
kkurt [141]

Answer:

1. N=120

2. n=2

3. N=66

4. n=5

5. N=21

6. n=20

7. n=1398

8. n=5

Step-by-step explanation:

1.

N-80=40

N=40+80

N=120

2.

15n=30

\dfrac{15n}{15}=\dfrac{30}{15}

n=2

3.

N+284=350

N=350-284

N=66

4.

6+9=3\times n

15=3n

\dfrac{15}{3}=n

n=5

5.

\dfrac{N}{3}=6+1

\dfrac{N}{3}=7

N=7\times 3

N=21

6.

12-8=\dfrac{n}{5}

4=\dfrac{n}{5}

4\times 5=n

n=20

7.

58\times 6=n-(723 + 327)

348=n-1050

348+1050=n

1398=n

8.

4n+12=(7+9)\times 2

4n+12=16\times 2

4n+12=32

4n=32-12

4n=20

n=\dfrac{20}{4}

n=5

Therefore, the solutions are 1. N=120

2. n=2

3. N=66

4. n=5

5. N=21

6. n=20

7. n=1398

8. n=5

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Step-by-step explanation:

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Explain how you can determine the sign of the sum of two integers if one integer is positive and the other integer is negative.
Neporo4naja [7]

Answer:

To add integers with different signs, keep the sign of the number with the largest absolute value and subtract the smallest absolute value from the largest.

Step-by-step explanation:

So, here's an example.

Lets say you have this problem:

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The answer would be 1 because when you add integers with different signs, you keep the sign of the number with the largest absolute value and subtract the smallest absolute value from the largest.

Here's another:

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The answer would be 5 because you keep the sign of the number with the largest absolute value and subtract the smaller absolute value from it.

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3 years ago
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