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2 years ago

Can someone help me with this question

Mathematics

1 answer:

olga2289 [7]2 years ago

6 0

Answer: $\displaystyle d=3\sqrt{5}$

Step-by-step explanation:

First, we will find the coordinate placement of each point. See attached.

Now, we can use the distance formula.

$\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}$

$d=\sqrt{(6-3)^2 +(-3-3)^2}$

$d=\sqrt{(3)^2 +(-6)^2}$

$d=\sqrt{9+36}$

$d=\sqrt{45}$

$d=\sqrt{9*5}$

$\displaystyle d=3\sqrt{5}$

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Which is better 4:3 odds or 3:4 odds? Why?

juin [17]

Answer:

no problem?

Step-by-step explanation:

8 0

3 years ago

1.dilate by 3/5 : (20,10)

inysia [295]

Answer:

a) )12,6)

b) (12,2)

c) (4,-7)

d) (9,-7)

Step-by-step explanation:

a) Dilation

When we dilate, we multiply the given scale factor by each of the coordinates

We have this as follows;

(20 * 3/5, 10 * 3/5) = (12, 6)

2. Here, we will add 5 to the x-axis value and subtract 6 from the y-axis value

We have this as;

(7+ 5, 8-6) = (12,2)

3. By reflecting across the x-axis

we have (x,y) changing to (x,-y)

so we have ;

(4,7) becomes (4,-7)

4. Rotation by 270 degrees (7,9)

If clockwise;

(x,y) becomes (y,-x)

so we have

(7,9) becoming (9,-7)

4 0

3 years ago

Question 2 Multiple Choice Worth 5 points)

DerKrebs [107]

Answer:

√20 units.

Step-by-step explanation:

Please see attached photo for diagram.

The other leg of the triangle is x as shown in the attached photo.

Using the pythagoras theory, we can obtain the the value of x as follow:

x² = 4² + 2²

x² = 16 + 4

x² = 20

Take the square root of both side.

x = √20 units

Therefore, the value of the other leg x of the triangle is √20 units

5 0

3 years ago

Help on this dccr Pleaseeeeeeee

forsale [732]

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4.Written
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7 0

3 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago