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Marta_Voda [28]
2 years ago
15

Can someone help me with this question

Mathematics
1 answer:
olga2289 [7]2 years ago
6 0

Answer: \displaystyle d=3\sqrt{5}

Step-by-step explanation:

     First, we will find the coordinate placement of each point. See attached.

     Now, we can use the distance formula.

\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}

d=\sqrt{(6-3)^2 +(-3-3)^2}

d=\sqrt{(3)^2 +(-6)^2}

d=\sqrt{9+36}

d=\sqrt{45}

d=\sqrt{9*5}

\displaystyle d=3\sqrt{5}

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hi im 7th grade and i feel like people think i smell when i do everything to not smell. i wake up take a shower with soap aplly
mr_godi [17]

Answer:

Step-by-step explanation:

This might be a hygiene problem. What causes the unpleasant smell is the bacteria that build up on your sweaty skin and react with sweat and oils to grow and multiply when sweat reacts with bacteria on the skin. These bacteria break down proteins and fatty acids, causing body odor in the process. If deodorant isn’t good enough , I recommend perfume, the perfume smell lasts longer than deodorant I would think. But shower everyday, full clean down, but if ur hygiene is ok, I recommend going to the doctor for a checkup. Hopefully your problem will be resolved. Also use lotion.

7 0
3 years ago
I NEED HELP WILL GIVE BRAINLIEST!! PLEASE HELP ME ASAP!!!!
GenaCL600 [577]

Answer:

A. The length of the second leg is 8.5 inches

B. The length of the three-dimensional diagonal is 9.9 inches

Step-by-step explanation:

Let us revise the relation between the hypotenuse and the two legs of a right triangle

(hypotenuse)² = (vertical leg)² + (horizontal leg)²

∵ The length of the rectangular box = 8 inches

∵ The width of the rectangular box = 3 inches

∵ The height of the rectangular box = 5 inches

∵ Length and width are perpendicular to each other

∴ The Δ whose legs are 3 and 8 is a right triangle

In the right Δ whose legs are 3 and 8

∵ (hypotenuse)² = (3)² + (8)²

∴ (hypotenuse)² = 9 + 64

∴ (hypotenuse)² = 73

- Take √  for both sides

∴ hypotenuse = \sqrt{73} = 8.544003745

- Round it to the nearest tenth of one inch

∴ hypotenuse = 8.5 inches

A.

The 3-dimensional diagonal is the hypotenuse of a right triangle whose legs are the vertical edge and the hypotenuse of the right triangle whose legs are 3 and 8

∵ The hypotenuse of the right triangle whose legs are 3 and

   8 is 8.5 inches

∴ The length of the second leg is 8.5 inches

B.

In the right triangle whose hypotenuse is the 3-dimensional diagonal and legs are the vertical edge , the hypotenuse of the right triangle whose legs are 3 and 8

∵ (3-dimensional diagonal)² = (5)² + (73)²

∴ (3-dimensional diagonal)² = 25 + 73

∴ (3-dimensional diagonal)² = 98

- Take √ for both sides

∴ 3-dimensional diagonal = \sqrt{98} = 9.899494937

- Round it to the nearest tenth of an inch

∴ 3-dimensional diagonal = 9.9 inches

∴ The length of the three-dimensional diagonal is 9.9 inches

<em>V.I.N: you can find the length of the  three-dimensional diagonal by using this rule → </em>d=\sqrt{l^{2}+w^{2}+h^{2}}<em> </em>

3 0
4 years ago
Domain and Range: determine the domain and Range for each graph
bija089 [108]

Given:

The graph of a function.

To find:

The domain and range of the given graph.

Solution:

Domain is the set of x-values or input values.

From the given graph it is clear that, the graph is defined for the interval (-4,4).

But there is a closed circle at x = -4 and an open circle at x = 4. It means, -4 is included and 4 is not included in the solution set.

Domain: [-4,4)

Domain: -4\leq x

Range is the set of y-values or output values.

From the given graph it is clear that, the output values are lie in the interval (-3,4).

But there closed circle at x = -3 and x = 4. It means, -3 and 4 are is included in the set of output values.

Range: [-3,4]

Range: -3\leq y\leq 4

Therefore, domain is -4\leq x and range is -3\leq y\leq 4.

7 0
3 years ago
What is the probability of randomly selecting a card from a standard 52 card deck and having the card be a face card or an even
Kobotan [32]
I think c but don’t take my word
4 0
3 years ago
I went to the grocery store the other day and there were no price tags on anything! I bought 3 loaves of bread and 1 milk jug an
Lostsunrise [7]
To solve this problem, set up and solve a system of equations.  The variables b and m will represent a bread loaf and milk jug, respectively:

\left \{ {{3b + m = 9} \atop {b + 2m =5.5}} \right.

I would solve using substitution.  Take one of the equations and set it equal to one of the variables, for example:

3b + m =9 \\ m = 9 -3b

Now, plug this into the other equation for m and solve for b:

b + 2m =5.5 \\ b + 2(9-3b)= 5.5 \\ b + 18 - 6b = 5.5 \\ -5b + 18 = 5.5 \\ -5b = -12.5 \\ b = 2.5

We now know that a loaf of bread costs $2.50.  Plug this value in for b in the first equation and solve for m:

3b + m = 9 \\ 3(2.5) + m = 9 \\ 7.5+m = 9 \\ m = 1.5

One jug of milk costs $1.50 and one loaf of bread costs $2.50.
8 0
3 years ago
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