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Marta_Voda [28]
2 years ago
15

Can someone help me with this question

Mathematics
1 answer:
olga2289 [7]2 years ago
6 0

Answer: \displaystyle d=3\sqrt{5}

Step-by-step explanation:

     First, we will find the coordinate placement of each point. See attached.

     Now, we can use the distance formula.

\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}

d=\sqrt{(6-3)^2 +(-3-3)^2}

d=\sqrt{(3)^2 +(-6)^2}

d=\sqrt{9+36}

d=\sqrt{45}

d=\sqrt{9*5}

\displaystyle d=3\sqrt{5}

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A rectangle has a length of 5.50 m and a width of 12.0 m. What are the perimeter and area of this rectangle?
natulia [17]
Perimeter is all the sides added together so 5.50 + 12 + 5.50 + 12 = 35 and area is base times height so 5.5 × 12 = 66

P = 35m
A = 66m
3 0
3 years ago
Blake and Josh are both saving money for a new bike. The ratio of Blake's savings to Josh's savings is 3:1. If they have saved $
kompoz [17]

Given:

Total savings = $400

Ratio of savings of Blake and Josh = 3:1

To find:

The saving of each.

Solution:

Let the savings of Blake and Josh are 3x and x respectively.

According to the question,

3x+x=400

4x=400

Divide both sides by 4.

x=100

Now,

Savings of Blake = 3(100)=300

Savings of Josh =100

Therefore, the savings of Blake and Josh are $300 and $100 respectively.

4 0
3 years ago
What’s the comparison to 3/25 and 22/25
In-s [12.5K]

Answer:

This is the answer. Hope it helps

Step-by-step explanation:

3/25<22/25

5 0
3 years ago
(5x3 + 48x2 + 25x − 18) ÷ (x + 9)
Lorico [155]
(x+1)•(5x-2) hope this helps
5 0
3 years ago
John has decided to prepare an old field for his son's new horse. the length of the field is 10 meters less than 4 times its wid
tatuchka [14]

Answer: The total money invested in the field will be $1,623.80

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

p=2(x+y)

p(4.80)=1,584

p=330m

we know that

The perimeter of the field is equal to

so

330=2(x+y)----> equation A

x=4y-10 ------> equation B

substitute equation B in equation A and solve for y

330=2(4y-10+y)

165=(5y-10)

5y=165+10

y+35

Find the value of x

x=4(35)-10+130

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

A=xy

substitute

A=(130)(35)=4,550m2

step 3

Find the number of bags of seed

Divide the area by 460

4,550/460=9.89 bags

Round up to the nearest whole number

9.89 bags=10 bags

step 4

Find the cost of the seed

(10 )(3.98)=$19.8

step 5

Find the total money invested in the field

1,584+$39.8=$1,623.80

7 0
2 years ago
Read 2 more answers
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