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igomit [66]
3 years ago
6

Match the words with their definitions.

Mathematics
1 answer:
NemiM [27]3 years ago
6 0

Answer:

denominator-of a fraction the number below the horizontal bar

numerator-of a fraction the number above the horizontal bar

fraction- ??? I don't see the definition

decimal fraction-symbol with three parts: a horizontal bar, a whole number above the bar, and a whole number below the bar number what's up value less than one, written place value notation, using a decimal point

percent-per hundred; out of every hundred; hundredths

improper fraction - fraction with a numerator greater than its denominator, giving it a value greater than 1

mixed number - number with a whole number part and a fraction part

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PLS HELPP WHAT IS THE ANSWER???
Elena-2011 [213]

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-220

Step-by-step explanation:

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Giving a test to a group of students, the grades and gender are summarized below
GenaCL600 [577]

Answer:

59 / 71

Step-by-step explanation:

Given the data :

A B C Total

Male 20 10 13 43

Female 15 2 11 28

Total 35 12 24 71

The probability of randomly selecting a Student that got B ;

Probability = required outcome / Total possible outcomes

P(getting B) = number of students who got B / total number of students

P(getting B) = 12 / 71

Probability of getting B = 12 /71

Probability of not getting B = P(getting B)' = 1 - P(getting B)

Probability that student did not get "B" = 1 - 12/71 = 59 / 71

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3 years ago
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If (5x− 4)(3x+ 7) = 15x²-ax-b,then find the value of a and b
Mkey [24]

Answer:

a=-23\\\\b=28

Step-by-step explanation:

Let's start by using distributive multiplication:

(a\pm b)(c\pm d)=ac\pm ad \pm bc \pm bd

So:

(5x-4)(3x+7)=15x^2+35x-12x-28\\\\

Grouping like terms:

15x^2 +(35x-12x)-28\\\\15x^2+23x-28

Now, 15x^2+23x-28 is equal to:

15x^2-ax-b

In this sense:

15x^2+23x-28=15x^2-ax-b

In order to satisfied the equality:

23x=-ax\hspace{10}(1)\\\\and\\\\-28=-b\hspace{10}(2)

Hence, from (1), let's solve for a:

23x=-ax\\\\-a=\frac{23x}{x} \\\\-a=23\\\\a=-23

And from (2), let's solve for b:

-28=-b\\\\b=28

Let's verify the result evaluating the values of a and b into the original equation:

(5x-4)(3x+7)=15x^2+23x-28=15x^2 -ax -b\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 -(-23)x -(28)\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 +23x -28

As you can see, the values satisfy the equation, therefore, we can conclude they are correct.

3 0
3 years ago
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