Answer:
the answer is 80
Step-by-step explanation:
8x2x5=80
LxWxH
Also, I had this soooo
We have been given that a circle of a certain radius has an area which is numerically 5 times the value of the circumference. We are asked to find the radius of the circle.
We know that area of circle with a radius of r units is
.
We know that circumference of a circle is
.
5 times the value of circumference would be
.
Now we will equate 5 times circumference with area as:

Let us solve for r.



Therefore, the radius of the circle would be 10 units.
There are two ways to do this
Method 1:
Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1
Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38
-----------------------------------------
Method 2:
Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48
Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10
Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38
-----------------------------------------
Whichever method you pick, the answer is: 38
X=45
y=-8
check if this work
Answer:
x = 1 1/4
Step-by-step explanation:
sqrt( 7x+2) = sqrt(3x+7)
Square each side
(sqrt( 7x+2))^2 = (sqrt(3x+7))^2
7x+2 = 3x+7
Subtract 3x from each side
7x-3x +2 = 3x+7-3x
4x+2 = 7
Subtract 2 from each side
4x+2-2 = 7-2
4x = 5
Divide by 4
4x/4 = 5/4
x = 1 1/4
Check for extraneous solution
sqrt( 7*5/4+2) = sqrt(3*5/4+7)
sqrt( 35/4 + 8/4) = sqrt(15/4+28/4)
sqrt( 43/4) = sqrt(43/4)
Solution is valid