<span>6(-3r)=-39+3r
-18r = -39+3r
39 = 18r + 3r
39 = 21r
39/21 = r
13/7 = r
r = 13/7</span>
The speed for which Brian iron the shirts is given by:
![R = \frac{\frac{2}{9}}{3\frac{3}{5}}](https://tex.z-dn.net/?f=%20R%20%3D%20%5Cfrac%7B%5Cfrac%7B2%7D%7B9%7D%7D%7B3%5Cfrac%7B3%7D%7B5%7D%7D%20%20%20%20%20%20)
Rewriting we have:
![R = \frac{\frac{2}{9}}{\frac{18}{5}}](https://tex.z-dn.net/?f=%20R%20%3D%20%5Cfrac%7B%5Cfrac%7B2%7D%7B9%7D%7D%7B%5Cfrac%7B18%7D%7B5%7D%7D%20%20%20%20%20%20)
![R = \frac{10}{162}](https://tex.z-dn.net/?f=%20R%20%3D%20%5Cfrac%7B10%7D%7B162%7D%20%20%20)
Then, for each minute, we have the amount of ironed shirt is:
![(\frac{10}{162})(1) = \frac{10}{162}](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B10%7D%7B162%7D%29%281%29%20%3D%20%5Cfrac%7B10%7D%7B162%7D%20%20%20%20)
Answer:
At this rate, Brian plans 10/162 of his shirt.
Problem # 1
3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)
problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12
(-1) (-2t) > 12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
t > -6 (t is greater then negative 6)
Solution:
![f(x)=2^{(x-5)}\\f(8)=2^{(8-5)}\\f(8)=2^{(3)}\\f(8)=8](https://tex.z-dn.net/?f=f%28x%29%3D2%5E%7B%28x-5%29%7D%5C%5Cf%288%29%3D2%5E%7B%288-5%29%7D%5C%5Cf%288%29%3D2%5E%7B%283%29%7D%5C%5Cf%288%29%3D8)
Answer:
8
<em>Hope this was helpful.</em>
Answer:
Yes for the first, no for the second