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3 years ago

The horizontal angle between objects can be measured by: _____

1 answer:

6 0

Even though a protractor is also used, the best way to meaure an horizontal angle between objects is by means a magnetic compass, used in topography

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What are the domain and range of the function h(x) = - + (x - 4)2 + 3?

lisov135 [29]

Answer:

(- infinite, infinite) , {x| x sum r}

range ) (-infinite. infinite) .{y|sumR}

Step-by-step explanation:

graphic picture

3 0

3 years ago

who this number in least to greatest on number line 0.4 space 1.2 space 2.5 Space 3 space 1.7put this number in least to greates

prohojiy [21]

Least -> Greatest:

.4 ; 1.2 ; 1.7 ; 2.5 ; 3

Hope this helps!

4 0

4 years ago

Please help me with this question

telo118 [61]

Answer:

C, because minus is difference and plus is the sum

7 0

3 years ago

Percent of change markup discount

vichka [17]

You calculate the markup or markdown in absolute terms (you find by how much the quantity changed), and then you calculate the percent change relative to the original value. So they're really just another form of "increase - decrease" exercises.

Example:

A computer software retailer used a markup rate of 40%. Find the selling price of a computer game that cost the retailer $25.
The markup is 40% of the $25 cost, so the markup is:

(0.40)(25) = 10
Then the selling price, being the cost plus markup, is:

25 + 10 = 35

The item sold for $35.

4 0

3 years ago

Read 2 more answers

In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be s

Sladkaya [172]

Answer:

The minimum sample size required is 5,499 computer users.

The major obstacle is that it is a big sample size if it is a small organization wanting to perform it.

Step-by-step explanation:

We need to calculate a sample size in order to have 95% confidence interval with 12 minutes of witdth.

So, we have that the difference between the upper limit and the lower limit is 12:

$UL-LL=12$

$(\mu+z*\sigma/\sqrt{n})-(\mu-z*\sigma/\sqrt{n})=12\\\\2z\sigma/\sqrt{n}=12\\\\\sqrt{n}=(1/6)*z\sigma\\\\n=(1/36)z^2\sigma^2$

For a 95% CI, the value of z is 1.96. The standard deviation is 227.

$n=z^2\sigma^2/36=(1.96)^2*(227)^2/36=3.8416*51,529/36=5498.72\\\\n=5499$

The minimum sample size required is 5,499 computer users.

6 0

3 years ago