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Hunter-Best [27]
2 years ago
12

I NEED HELP ASAP PLEASE HELP ME!!

Mathematics
1 answer:
UkoKoshka [18]2 years ago
7 0

Answer:

Step-by-step explanation:

See attached image

You might be interested in
Can the sides of a triangle have lengths 3.5, 10.9, and 14.4?
andrew11 [14]

Answer:

No

Step-by-step explanation:

A triangle can NOT have those lengths because any side of a triangle has to have a length greater than the sum of the other two sides. In this case, 14.4, one of the sides, is not greater than the sum of the other two sides (which is also 14.4).

Hope this helps :)

4 0
2 years ago
If C is the midpoint of EF, C has coordinate -8, F has coordinate 4, then find the coordinate of E
ycow [4]
<h3>Answer:    -20</h3>

==========================================================

Work Shown:

Let x be the location of E on the number line.

Since C is the midpoint of E and F, this means we can find C's location by adding E and F together and dividing that sum by 2

midpoint = (endpoint1 + endpoint2)/2

C = (E+F)/2

Plug in E = x, C = -8 and F = 4. Then solve for x

C = (E+F)/2

-8 = (x+4)/2

(x+4)/2 = -8

x+4 = 2(-8) .... multiplying both sides by 2

x+4 = -16

x = -16-4 .... subtract 4 from both sides

x = -20

The location of point E on the number line is -20

-------------

As a check, lets add E and F to get E+F = -20+4 = -16

Then cut this in half to get -16/2 = -8, which is the proper location of point C

This confirms our answer.

8 0
3 years ago
The game of Connex contains one 4-unit piece, two identical 3-unit pieces, three identical 2-unit pieces and four identical 1-un
Aleks [24]

Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

= 20permutations

4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

= 5*6

= 30 permutations

6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

= 30 permutations

Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

= 5*4

= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

= 6*10

= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

5 0
2 years ago
Find me equation of the circle with Center at ( 3, - 2) and radius of 3
blondinia [14]

The equation of a circle with center (x_0,y_0) and radius r is

(x-x_0)^2+(y-y_0)^2=r^2

In your case,

x_0=3,\quad y_0=-2,\quad r=3

Plug these values into the generic formula and you'll get your equation.

5 0
3 years ago
Will is twice as old as Jill. Three years ago, Jill's age was two fifths of Will's age then. How old is each now?
dimulka [17.4K]
"Will is twice as old as Jill."

                       Jill's age . . . . .   J
                       Will's age . . . . 2J .

"Three years ago . . .

                       Jill's age then . . . . .   J - 3
                       Will's age then . . . . 2J - 3

". . . Jill's age then was 2/5 of Will's age then."

                                         J - 3  =  (2/5) (2J - 3)
Multiply
each side by  5 :          5J - 15  =  2 (2J - 3)

Divide
each side by  2 :          2.5 J - 7.5  =  2J - 3 

Subtract  2J
from each side:            0.5 J - 7.5  =      -3

Add  7.5
to each side:                0.5 J           =     4.5

Multiply
each side by  2 :                J            =       9

Jill is  9  y.o. now.
Will is 18 y.o. now.

4 0
2 years ago
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