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Ede4ka [16]
2 years ago
12

(1 2/3 - 3/5) / 3 * 1/2 + 1/3

Mathematics
2 answers:
Vlad [161]2 years ago
7 0

Answer:

23/45

Step-by-step explanation:

Paladinen [302]2 years ago
4 0

Answer:

23/45

Step-by-step explanation:

1) Convert 1\frac{2}{3}  to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}

\frac{\frac{1\times 3+2}{3}-\frac{3}{5}}{3}\times \frac{1}{2}+\frac{1}{3}

2) Simplify 1\times 3 to  3.

\frac{\frac{3+2}{3}-\frac{3}{5}}{3}\times \frac{1}{2}+\frac{1}{3}

3) Simplify  3+2  to  5.

\frac{\frac{5}{3}-\frac{3}{5}}{3}\times \frac{1}{2}+\frac{1}{3}

4)  Find the Least Common Denominator (LCD) of \frac{5}{3},\frac{3}{5}. In other words, find the Least Common Multiple (LCM) of 3,5.

Method 1: By Listing Multiples

1 -  List the multiples of each number.

Multiples of 3 : 3, 6, 9, 12, 15, ...

Multiples of 5 : 5, 10, 15, ...

2 -  Find the smallest number that is shared by all rows above. This is the LCM.

LCM = 15

Method 2: By Prime Factors

1- List the prime factors of each number.

Prime Factors of 3 : 3

Prime Factors of 5 : 5

2 - Find the union of these primes.

3, 5

3- Multiply these numbers:3\times 5=15,. This is the LCM.

LCM = 15

5) Make the denominators the same as the LCD.

\frac{5\times 5}{3\times 5}-\frac{3\times 3}{5\times 3}

6) Simplify. Denominators are now the same.

\frac{25}{15}-\frac{9}{15}

7) Join the denominators.

\frac{25-9}{15}

8) Simplify\frac{5}{3}-\frac{3}{5}  to \frac{16}{15}

\frac{\frac{16}{15}}{3}\times \frac{1}{2}+\frac{1}{3}

9) Simplify  \frac{\frac{16}{15}}{3} to    \frac{16}{15\times 3}.

\frac{16}{15\times 3}\times \frac{1}{2}+\frac{1}{3}

10) Simplify 15\times 3 to  45.

\frac{16}{45}\times \frac{1}{2}+\frac{1}{3}

11)  Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}.

\frac{16\times 1}{45\times 2}+\frac{1}{3}

12) Simplify 16\times 1 to  16.

\frac{16}{45\times 2}+\frac{1}{3}

13) Simplify  45\times 2  to  90.

\frac{16}{90}+\frac{1}{3}

14) Simplify \frac{16}{90} to \frac{8}{45}.

\frac{8}{45}+\frac{1}{3}

15) Find the Least Common Denominator (LCD) of \frac{8}{45},\frac{1}{3} . In other words, find the Least Common Multiple (LCM) of 45, 3.

Method 1: By Listing Multiples

1 - List the multiples of each number.

Multiples of 45 : 45, ...

Multiples of 3 : 3, 6, 9, ... , 39, 42, 45, ...

2 -  Find the smallest number that is shared by all rows above. This is the LCM.

LCM = 45

Method 2: By Prime Factors

1 - List the prime factors of each number.

Prime Factors of 45 : 3, 3, 5

Prime Factors of 3 : 3

2 -  Find the union of these primes.

3, 3, 5

Multiply these numbers: 3\times 3\times 5=45. This is the LCM.

LCM = 45

Result: LCD=45

16)  Make the denominators the same as the LCD.

\frac{8}{45}+\frac{1\times 15}{3\times 15}

17) Simplify. Denominators are now the same.

\frac{8}{45}+\frac{15}{45}

18)  Join the denominators.

\frac{8+15}{45}

19) Simplify.

\frac{23}{45}

Decimal Form: 0.511111

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Step-by-step explanation:

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I=prt,for p please show step by step for this variable
Bond [772]

Answer:

p = \dfrac{I}{rt}

Step-by-step explanation:

I = prt

Switch sides.

prt = I

We are solving for p. We want p alone on the left side. p is being multiplied by r and t, so we divide both sides by r and t.

\dfrac{prt}{rt} = \dfrac{I}{rt}

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How is the pattern changing to get from one term to the next? 55, 49, 43, 37, 31,...
ZanzabumX [31]

Answer:

C.

Step-by-step explanation:

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6 0
3 years ago
the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region​
m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

\frac{x}{360} \pi {r}^{2}

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

16 =  \sqrt{10 {}^{2} + 10 {}^{2}   - 2(100) \times  \cos(o) }

This isn't the standard formula, it's for this problem

16 =  \sqrt{200 - 200 \times  \cos(o) }

16 =  \sqrt{200  - 200 \cos(o) }

256 = 200 - 200 \cos(o)

56 =  - 200 \cos(o)

-  \frac{7}{25}  =  \cos(o)

\cos {}^{ - 1} (  - \frac{7}{25} )  =  \cos {}^{ - 1} ( \cos(o) )

106.26 = o

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

\frac{106.26}{360} (100)\pi

\frac{10626}{360} \pi

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

\sqrt{s(s - a)(s - b)(s - c)}

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

\frac{36}{2}  = 18

\sqrt{18(18 - 10)(18 - 10)(18 - 16)}

\sqrt{18(8)(8)(2)}

\sqrt{(36)(64)}

6  \times 8 = 48

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

\frac{10626}{360}  - 48

Which is an approximate or

44.73

6 0
2 years ago
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