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Alona [7]
2 years ago
13

Morgan pays $25 in monthly fees for her baseball team's uniforms and field rental. What kind of expense is the fee she pays? I d

on't know what the answer is
Mathematics
1 answer:
Colt1911 [192]2 years ago
7 0

Answer:

Miscellaneous Expenses

Step-by-step explanation:

Given that Miscellaneous Expenses are a type of expense that defines the non-major expenditures which cannot be categorized as any of the manufacturing, selling, and administrative costs.

And according to Internal Revenue Service, expenses that do not conform to one of their tax categories are considered Miscellaneous Expenses, for example, clothing, and rent payments are a form of Miscellaneous Expenses.

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Help with question number one please
coldgirl [10]

Answer:

165 hits

Step-by-step explanation:

27.5% of 600 is 600 x 27.5 / 100 = 165

4 0
2 years ago
Diameter =9.4mm what is the area?​
Likurg_2 [28]

Answer:

here

Step-by-step explanation:

0.10757 square inches (in²)

7 0
2 years ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

8 0
1 year ago
The length of a rectangle is 4 more than twice the width. The perimeter is 74 feet. Find the length and width of the rectangle.
mafiozo [28]
(2*length)+(2*width)=perimeter
length=4+2w
(2(4+2w))+(2(w))=74
74=(8+4w)+(2w)
74=6w+8
66=6w
w=11
length=4+2(11)
l=4+22
l=26
3 0
3 years ago
Given the Quadratic, determine the value of the discriminant.<br> 2x2 – 3x – 20 = 0
Andrews [41]
2x2-3x-20=0
4-3x-20=0
2-20=-16
-3x-16=0
-3x=16
x= -5.33333
I think i did it right. i hope this helps.
4 0
3 years ago
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