!PLEASE HELP!

Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π). (Enter your answers as a comma-separated list

lara31 [8.8K]

Sin(2θ)+sin(θ)=0
use double angle formula: sin(2θ)=2sin(θ)cos(θ).
=>
2sin(θ)cos(θ)+sin(θ)=0
factor out sin(θ)
sin(θ)(2cos(θ)+1)=0
by the zero product property,
sin(θ)=0 ...........(a) or
(2cos(θ)+1)=0.....(b)
Solution to (a): θ=k(π)
solution to (b): θ=(2k+1)(π)+/-(π)/3
for k=integer

For [0,2π), this translates to:
{0, 2π/3,π,4π/3}

8 0

3 years ago

what is the answer for 1/3x+y=4 and if you use big ideas math program and you got the right answer lemme know

erica [24]

Answer:

x=-3y+12

Step-by-step explanation:

Yes.

8 0

3 years ago

Find the probability that a point is chosen randomly inside the rectangle is in each given shape...

Arlecino [84]

By taking the quotients between the areas, we see that:

a) P = 0.275
b) P = 0.85

<h3>How to find the probabilities?</h3>

First we need to find the areas of the 3 shapes.

For the triangle, the area is:

T = 3*5/2 = 7.5

For the blue square, the area is:

S = 3*3 = 9

For the rectangle, the area is:

R = 10*6 = 60

Now, what is the probability that a random point lies on the triangle or in the square?

It is equal to the quotient between the areas of the two shapes and the total area of the rectangle, this is:

P= (7.5 + 9)/60 = 0.275

b) The area of the rectangle that is not the square is:

A = 60 - 9 = 51

Then the probability of not landing on the square is:

P' = 51/60 = 0.85

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

6 0

3 years ago

What’s the correct answer for this ?

Ann [662]

Answer:

8/3

9/11

try it. and send money :)

5 0

2 years ago

A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute. A fire hydrant with a green cap provides wa

lapo4ka [179]

Answer:

a) 2b = 3g

b) 3p = b

Step-by-step explanation:

Given:

Fire hydrant with a blue cap, b, provides water at a rate = 1500 gallons per min

Fire hydrant with a green cap, g, provides water at a rate = 1000 gallons per min

Fire hydrant with a purple cap, p, provides water at a rate = ½g = $\frac{1}{2}*1000 = 500$

a) The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g.

Given flow of blue hydrant, b = 500

Simplifying, we have:

b = 3*500

$b = 3 * \frac{1000}{2}$

Since the flow rate of green hydrant, g, is 1000, let's replace 1000 with g above.

Therefore,

$b = 3 * \frac{g}{2}$

$b = \frac{3}{2}g$

Cross multuply

$2b = 3g$

The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g is 2b=3g.

b) An equation to relate the flow of water from the purple hydrant, p, to the flow from the blue hydrant, b.

Given flow rate of purple hydrant, p = 500

It could also be re-written as:

$\frac{3}{3} * 500$

$p = \frac{1500}{3}$

Since the flow rate of blue hydrant, b, is 1500, let's replace 1500 with b above.

$p = \frac{b}{3}$

Cross multiply

3p = b

8 0

3 years ago