Case a: A student can receive any number of awards
Let's count our choices: the first award can go to any of the 20 students. So we have 20 choices. The second awards can also go to any of the 20 students. So we have 20*20 choices for the first two awards. Similarly, we have 20*20*20 choices for the first three awards, and so on.
So, there are possible ways to give the awards, if a student can receive as many awards as possible.
Case b: A student can receive only one awards
This will be very similar to the previous case, but with a minor restriction: as before, we have 20 choices for the first award, because it can go to any of the 20 students.
But when it comes to the second award, we only have 19 choices, because we can't give it to the student who already won the first award.
Similarly, we can give the third award to one of the 18 remaining students, because we can't give it to the students who already won the first or second award.
So, in the end, we have
ways of awarding the students, if a student can win only one award.
Answer:
90 cm²
Step-by-step explanation:
since the ratio is 1:6 for every one little box the bigger box increases 6 times.
so 15·6= 90 cm²
Answer:
70%
Step-by-step explanation:
Well, you have 3 hours to work with, which is 180 minutes. You subtract 30 minutes from warm up, then subtract another 24 minutes for group work time, and you're left with 126 minutes. Now, to figure out the percent, you take 126 divided by the total time (3 hours or 180 minutes)
126 / 180 is 0.70, which as a percent is 70%.
Answer:
A. 27 / (6+c)
Step-by-step explanation:
If we assume Barry is spreading the cards among the suits, then he needs enough suits to hold the total of 27 cards he has. Thus, we need to divide the total number of cards by the total number of cards he puts in each suit, giving the option A as the correct answer.
I hope that works for you!