Answer:
5 cm
Step-by-step explanation:
The distance a coiled spring stretches varies directly with the amount of weight hanging on the spring.
Distance = D
Weight = W
Hence:
D ∝ W
D = kW
Where k is constant of proportionality
Step 1
We solve for k
If a spring stretches 2 cm when a 30 gram weight is hung from it.
2 = 30k
k = 2/30
k = 1/15
Step 2
how far will it stretch when a 75 gram weight is hung from the spring?
D = kW
We are solving for D
k = 1/15
D = 1/15 × 75
D = 5 cm
The spring would stretch 5cm with a weight of 75 gram.
Bisector must pass through the mid-point, so we have to find out that mid-point of the segment:
mid point = x₁+x₂ / 2 , y₁+y₂/2
= 1 + 5 / 2 , 1 + 7 / 2
= 6/2 , 8/2
= (3, 4)
Slope of given segment = m = y₂-y₁ / x₂- x₁
m = 7-1 / 5-1
m = 6/4
m = 3/2
Now, segment which is perpendicular, will have the opposite & reciprocal slope, So, it would be: -2/3
We know, y - y₁ = m(x - x₁)
y - 4 = -2/3(x - 3)
y - 4 = -2/3x + 2
y = -2/3x + 6
In short, Your Final Answer would be: y = -2/3x + 6
Hope this helps!
Answer:
24 m^2
Step-by-step explanation:
The dimensions of the base appear to be 6 m long and 4 m wide. In this case, the area of the base is A = (length)(width) = 24 m^2
Answer:
You would have $18
Step-by-step explanation:
Have a good day!
Answer: a) x = 5 or -1 b) x = √3+2
c) x = -1/2 or -3/2
Step-by-step explanation:
a) (x − 2)² = 9
First step is to take the square root of both sides to eliminate the square
√ (x − 2)² = √9
x-2 = +-3
x = +3+2
x = 5 and;
x = -3+2
x = -1
x = 5 or -1
b) 3(x-2)² = 9
First we divide both sides by 3 to get;
(x-2)² = 9/3
(x-2)² = 3
Second step is to take the square root of both sides to eliminate the square
√(x-2)² = √3
x-2 = √3
x = √3+2
c) 6 = 24(x+1)²
Dividing both sides by 24, we have
6/24 = (x+1)²
1/4 = (x+1)²
Taking the square root of both sides we have
√1/4 = √(x+1)²
= +-1/2 = x+1
x = +1/2-1 = -1/2 and;
x = -1/2-1 = -3/2
x = -1/2 or -3/2
