Hello from MrBillDoesMath!
Answer:
Limit does not exist.
Discussion:
The function 1/x has a vertical asymptote as x approaches 0 so
sin (pi/x) has no limit as x approaches 0. In fact, it oscillates wildly between -1 and 1 as x approaches 0. See attached graph of function
Thank you,
MrB
Answer:
y=−2x−10
Step-by-step explanation:
Multiplying and dividing with conjugate of 2+i in the given expression, we get(3+ 4i)(2-i)/(2+i)(2-i)=(6-3i+8i-4i^2)/(4-i^2)=(10+5i)/(4+1)=(10+5i)/5=2+i=a+bi<span>Thus a=2</span>