Question

Pls answer urgent will mark branliest asap

Answer 1

Answer:

$\frac{11+6\sqrt{3} }{52+30\sqrt{3} }$

Step-by-step explanation:

Simplifying

• $\frac{1}{(\sqrt{3+1)} ^{2} } + \frac{1}{(\sqrt{3}+2)^{2} }$
• $\frac{(\sqrt{3}+2)^{2}+(\sqrt{3+1)} ^{2}}{(\sqrt{3+1)} ^{2}(\sqrt{3+2)} ^{2}}$
• $\frac{3+4\sqrt{3}+4 +3+2\sqrt{3}+1 }{(3+4\sqrt{3}+4)(3+2\sqrt{3}+1)}$
• $\frac{11+6\sqrt{3} }{(7+4\sqrt{3})(4+2\sqrt{3})}$
• $\frac{11+6\sqrt{3} }{28+16\sqrt{3}+14\sqrt{3}+24 }$
• $\frac{11+6\sqrt{3} }{52+30\sqrt{3} }$

Answer 2

Answer:

$\frac{ 11+6\sqrt{3} }{(\sqrt{3}+1)^{2}( \sqrt{3}+2)^{2} }$

Step-by-step explanation:

Simplifying;

$\frac{1}{(\sqrt{3}+1)^{2} } +\frac{1}{(\sqrt{3}+2)^{2} }\\\\=\frac{(\sqrt{3}+2)^{2}+(\sqrt{3}+1)^{2}}{(\sqrt{3}+1)^{2}( \sqrt{3}+2)^{2} } \\\\=\frac{[(\sqrt{3})^{2} +(2)^{2}+2(\sqrt{3}) (2)]+[(\sqrt{3})^{2} +(1)^{2}+2(\sqrt{3}) (1)]}{(\sqrt{3}+1)^{2}( \sqrt{3}+2)^{2} } \\\\=\frac{[{3} +4+4(\sqrt{3}) ]+[{3} +1+2\sqrt{3}]}{(\sqrt{3}+1)^{2}( \sqrt{3}+2)^{2} }\\\\=\frac{[ 7+4\sqrt{3} +4+2\sqrt{3}]}{(\sqrt{3}+1)^{2}( \sqrt{3}+2)^{2} }\\\\=\frac{ 11+6\sqrt{3} }{(\sqrt{3}+1)^{2}( \sqrt{3}+2)^{2} }$