All categories

2 years ago

-86, 88, 33, 55, 93, 6, 88, 81, 5, -33, 33, -33

1 answer:

5 0

Answer:
27.5

Steps:
Add up the values then divide by the number of values.

In this case there is 12 values.
The sum of all values divided by 12.
27.5

You might be interested in

Problem 2 Example 2: Bruno spends $23 at the arcade. He purchased two drinks and spent $17 on games. What was the cost of each d

stiks02 [169]

Answer:

Step-by-step explanation:

23-17=6

6/2=3

To check:

6+17=23

3 0

3 years ago

Read 2 more answers

Can you help with this please

mojhsa [17]

Answer:

x = 81

Steps:

It says that y ~ √x

We have points (9, 18) as a guide.

We can write y = f(x) = a√x +b

Use points (9, 18) as a guide

18 = a√9 +b

18 = 3a + b

One solution might be a = 6, which means f(x) = 6√x

Thus when y = 54,

54 = 6√x

9 = √x

81 = x

6 0

2 years ago

Help me please and thank you!

lorasvet [3.4K]

Answer:

-4/3

Step-by-step explanation:

-2 - 1 is -3

6-2 is 4

6 0

3 years ago

Look at pic and answer pls

PtichkaEL [24]

(a) $x^{-5}$

(b) $3x^{-7}$

Solution:

To write each of the given expression in the form $ax^n$ :

(a) $\frac{x^3}{x^8}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$\frac{x^3}{x^8}=x^{3-8}$

$$\frac{x^3}{x^8}=x^{-5}$

(b) $\frac{6x}{2x^8}$

Divide numerator and denominator by the common factor 2, we get

$$\frac{6x}{2x^8}=\frac{3x}{x^8}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$=3x^{1-8}$

$$\frac{6x}{2x^8} =3x^{-7}$

Divide numerator and denominator by the common factor 7, we get

$$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$=\frac{4}{3}x^{6-2}$

$$\frac{28x^6}{21x^2}=\frac{4}{3}x^4$

8 0

3 years ago

Numbers 10, 100, 1,000, and so on are called

wlad13 [49]

I do believe that those are called numbers

8 0

3 years ago

Read 2 more answers