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3 years ago

5/8 plus 1/16 simplified

1 answer:

4 0

We want to make their denominators the same to add them, their common denominator is 16
So 5/8 will become 10/16
now we can add both fractions easily
10/16 + 1/16 = 11/16

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What fraction is 1 yard 2 feet and 6 inches

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Answer:

Make sure you convert these numbers into one unit. Convert everything to yard. Just convert the feet and inches in yard since it's the biggest unit, and then add them together. You should get a fraction not a whole number.

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3 years ago

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Jose just submitted his resume to a job posting. The posting started thats the job pays $47.588 annually. What would Jose’s mont

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3965.67 a month

Step-by-step explanation:

presuming you mean $47,588 annually.

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4 years ago

Name three other real-world situations where a strategy, "plan of attack, or

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Planning a wedding .

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3 years ago

What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?

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Answer-

The coordinates of the orthocenter of △JKL is (-4, 8)

Solution-

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

$JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117$

As,

$\Rightarrow 117=81+36$

$\Rightarrow JL^2=JK^2+KL^2$

$\Rightarrow \text{JKL is a right angle triangle}$

$\Rightarrow \angle K=90^{\circ}$

Therefore, the vertex at K (-4, 8) is the orthocentre.

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3 years ago

Which correctly describes a cross section of the cube below? Check all that apply.

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Answer:

B,E and F

Step-by-step explanation:

(B)A cross section parallel to the base is a square measuring 4 cm by 4 cm.

Since a cube has equal base length, any cross section parallel to the base will also have an equal base length.

(E)A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.

Since a cube has equal side lengths, any cross section parallel to the side will also have an equal base length.

(F)A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.

Using Pythagoras Theorem

$4^2+4^2=4\sqrt{2}>4$

There the cross section will be a rectangle which measures $4\sqrt{2}\:cm\:by\:4\:cm$

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3 years ago

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