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2 years ago

If x-2y=10 and x≠0, what is the value of 2x/y+5

Mathematics

1 answer:

VladimirAG [237]2 years ago

5 0

Answer: 4

Step-by-step explanation:

x - 2y =10

x = 10 + 2y

$\frac{2x)}{y + 5}$

$\frac{2(10+2y)}{y+5}$

$\frac{20+4y}{y+5}$

$\frac{4(5+y)}{y+5}$ ... cancel like terms (y + 5)

= 4

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In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th

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Answer:

$\frac{BE}{EC} =\frac{1}{3}$

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

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$\frac{AD}{BE} =\frac{4}{1}$

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$\frac{BE+EC}{BE}=\frac{4}{1}$ ( BC= BE+EC)

$\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}$

$1+\frac{EC}{BE}=4$

$\frac{EC}{BE}=3$ ( subtracting 1 from both side )

$\frac{EC}{BE}=\frac{3}{1}$

taking reciprocal both side

$\frac{BE}{EC} =\frac{1}{3}$

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