1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivan
1 year ago
9

If x-2y=10 and x≠0, what is the value of 2x/y+5

Mathematics
1 answer:
VladimirAG [237]1 year ago
5 0

Answer: 4

Step-by-step explanation:

x - 2y =10

x = 10 + 2y

\frac{2x)}{y + 5}

\frac{2(10+2y)}{y+5}

\frac{20+4y}{y+5}

\frac{4(5+y)}{y+5} ... cancel like terms (y + 5)

= 4

You might be interested in
Three more than the quotient of a number and 4 is equal to 8
inn [45]
3+ x/4=8


................

..
6 0
3 years ago
Identify the conclusion of the statement.
lorasvet [3.4K]

Answer:

its b

Step-by-step explanation:

5 0
2 years ago
The weight of a dog crate is 5.6 lbs. the crate and 3 puppies together weigh 36.35 lbs. estimate the weight of one puppy.
nata0808 [166]
36.35 - 5.6 = 30.75 ÷ 3 = 10.25

7 0
3 years ago
A car traveling at 88 km an hour over takes a bus traveling at 64 km an hour if the bus has a 1.5 hour Headstart how far from th
PIT_PIT [208]

Answer: 352 miles

Step-by-step explanation:

At the point where the car overtook the bus, the car and the bus would have travelled the same distance.

Let x represent the distance covered by bus and the car before the car overtook the bus.

Let t represent the time taken by the bus to travel x miles.

The bus was traveling at 64 km an hour.

Distance = speed × time

Distance travelled by the bus in t hours would be

x = 64 × t = 64t

if the bus has a 1.5 hour Headstart, it means that the car started moving 1.5 hours after the bus has moved.

Therefore, time spent by the car would be t - 15 hours.

The car traveling at 88 km an hour

Distance covered by the car in t - 1.5 hours would be

x = 88(t - 1.5) = 88t - 132

Since the distance covered is equal, then

88t - 132 = 64t

88t - 64t = 132

24t = 132

t = 132/24

t = 5.5 hours

Therefore, the distance from the starting point when the car overtook the bus would be

x = 64 × 5.5 = 352 miles

3 0
3 years ago
Consider the system of equations.
anzhelika [568]

Answer: You can multiply the top equation by -1 to eliminate the x variable.

And the solution is (2,4/3)  in case you need it.

Step-by-step explanation:

2x + 3y = 8

2x + 6y = 12

If you multiply the upper equation or down equation by one, you will be able to eliminate the x variable.

-1( 2x + 3y) = -1(8)     New equation:   -2x -3y  = -8.

Add the new equation you got  by multiplying the top equation by -1 to the bottom equation.

Add them:     -2x -3y = -8

                      2x + 6y = 12  

                               3y = 4  

                              y = 4/3

You can now input the value for y into the one of the equations and solve for x.

-2x - 3(4/3) = -8

-2x -4 = -8  

     +4     +4

-2x = -4

x = 2

8 0
3 years ago
Other questions:
  • Determine whether the given differential equation is exact. if it is exact, solve it. (if it is not exact, enter not.) (3x + 6y)
    11·1 answer
  • HELP!!!!!!!!!!!!!!!!!!!!!
    15·1 answer
  • Literally answer any of the questions above and it’ll be the biggest help
    7·1 answer
  • Ann can swim 20 laps in 8 min. how long will it take to swim 9 laps? show your equations(s).
    6·1 answer
  • Help!NOW please!! I’ll do anything!
    13·2 answers
  • Jeff is meeting billy at the park to play basketball at 2:30 p.m on the way to the park Jeff took 5 minutes stop and talk to his
    13·2 answers
  • I need help please! Thank you.
    15·1 answer
  • If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
    12·1 answer
  • 3. A barrel contained 60 gallons of water. Water leaked out of the barrel at a rate of 5
    5·1 answer
  • There were 560 people at a play. The admission price was $2 for
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!