<h3>Answer:</h3>
x = 2
<h3>Explanation:</h3>
The rule for secants is that the product of segment lengths (on the same line) from the point of intersection to the points on the circle is a constant for any given point of intersection. Here, that means ...
... 3×(3+5) = 4×(4+x)
... 6 = 4+x . . . . divide by 4
... 2 = x . . . . . . subtract 4
_____
<em>Comment on this secant relationship</em>
Expressed in this way, the relationship is true whether the point of intersection is inside the circle or outside.
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Given:
f(x) = ln(x)
n = 4
c = 3
nth Taylor polynomial for the function, centered at c
The Taylor series for f(x) = ln x centered at 5 is:

Since, c = 5 so,

Now
f(5) = ln 5
f'(x) = 1/x ⇒ f'(5) = 1/5
f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25
f'''(x) = 2/x³ ⇒ f'''(5) = 2/5³ = 2/125
f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625
So Taylor polynomial for n = 4 is:
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Hence,
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Find out more information about nth taylor polynomial here
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So, We Need To Write An Equation To Find This:
AD = lAl + lDl
So:
AD = l-7l + l8l
l-7l= 7.
AD = 7 + 8
7+8 = 15
AD = 15
So, AD = 15. This Means That The Answer Is B.
Answer:
x=-3
Step-by-step explanation:
The quadratic function
determines the parabola which has the vertex at point (-3,5). The axis of symmetry passes through the vertex and is parallel to the y-axis. Hence, its equation is x=-3 (see attached diagram).
Answer:
108
Step-by-step explanation:
50 + 4 = 54
54 x 2 = 108