Answer: The minimum reliability for the second stage be 0.979.
Step-by-step explanation:
Since we have given that
Probability for the overall rocket reliable for a successful mission = 97%
Probability for the first stage = 99%
We need to find the minimum reliability for the second stage :
So, it becomes:
P(overall reliability) = P(first stage ) × P(second stage)

Hence, the minimum reliability for the second stage be 0.979.
Given:
Either has a school certificate or diploma or even both = 20 people
Having school certificates = 14
Having diplomas = 11
To find:
The number of people who have a school certificate only.
Solution:
Let A be the set of people who have school certificates and B be the set of people who have diplomas.
According to the given information, we have



We know that,



Subtract both sides by 25.



We need to find the number of people who have a school certificate only, i.e.
.



Therefore, 9 people have a school certificate only.
Answer:
The value of x is 3/2.
Step-by-step explanation:
Given data in the question:-

We have to find the value x.
Let
be eq(i).
Solving eq (i)

using the properties of the exponents we have
if aⁿ=aˣ
then n=x

Hence the answer is 3/2.
The statement which describes what the equation tells is; The number of customers they have prior/before the review is; 500 customers.
- The number of customers they have 2 months after the review is; 222.22 customers.
<h3>Exponential functions</h3>
According to the given function;
- The intercept of the function represents the number of customers the restaurant has prior to the review.
This means the number of customers they have prior/before the review (at m=0) is; 500 customers.
Additionally, after 2 months of the review;
C = 222.22 customers
Read more on exponential functions;
brainly.com/question/2456547
Answer:
your english is very bad
Step-by-step explanation: