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Rama09 [41]
3 years ago
12

The quotient of a number r and 7 is no more than 18 inequality?

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:ikkdrrrrr

Step-by-step explanation:

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Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
Need help asap do tonight
aalyn [17]

Answer:

answer and explanation below

Step-by-step explanation:

2.m<x=75(angle on the same line so 180-105)

  m<y=105 (vertical angles of the parallelogram are equal)

 m<z=75 ( vertical angle of m<x)

3.M<y = 25 ( vertical angle property)

m<z=155( on the same line)

m<z and M,x =155( vertical angles )

8 0
3 years ago
Find the area of a square with a diagonal of 8cm.
klio [65]
You have to use the Pythagorean theorem but there is a little twist here since a square has has equal sides. So:
x^2+x^2=8
2x^2=8
2/2x^2=8/2
x^2=4
√x^2=√4
x=2
The side of the square is 2.
So now the area of a square is:
Side×Side
2×2=4
The area of the square is 4 centimetres
7 0
3 years ago
Factor the expression using the GCF: 12x + 36 *
Rashid [163]

The answer fam is.........12(x + 3)

6 0
3 years ago
Solve 19.9 = 9 y - 8.<br> Y=
Savatey [412]
The answer would be y = 3.1

19.9 + 8 = 9y

27.9 = 9y

27.9/9 = y

3.1 = y

y = 3.1.
3 0
3 years ago
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