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Nonamiya [84]
3 years ago
5

Greastest common factor please help me

Mathematics
2 answers:
loris [4]3 years ago
4 0

Answer:

6m

Step-by-step explanation:

12m+18m^2

6m(2+3m)

Hatshy [7]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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Step-by-step explanation:

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How does f(4) if f(x) = 2x work? how do i work this out?
sveta [45]
So just plug in the 4 wherever you see an x. so it is f(4)=2(4)
6 0
2 years ago
Y=3x−5 and y=x−1 ​ Is (2,1) a solution of the system?
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Step-by-step explanation:

7 0
3 years ago
Find the mean of the data summarized in the given frequency distribution . Compare the computed mean to the actual mean of 57.6
AlexFokin [52]

The mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F is lesser than the actual mean of 57.6° F.

<h3>What is the mean of a distribution?</h3>

The mean of the distribution can be defined as the average value of the distribution, It can be expressed as the total sum of all the observed values divided by the frequency of the distribution.

From the parameters given:

Low-temperature             Frequency

40 - 44                                    2

45 - 49                                    5

50 - 54                                    9

55 - 59                                    6

60 - 64                                    3

The first thing to do is to determine the class midpoint. The class midpoint is the sum of the class interval divided by 2.

The class midpoint of 40 - 44 is \mathbf{\dfrac{40 + 44}{2} = 42}

The class midpoint of 45 - 49 is \mathbf{\dfrac{45 + 49}{2} = 47}

The class midpoint of 50 - 54 is \mathbf{\dfrac{50 + 54}{2} = 52}

The class midpoint of 55 - 59 is \mathbf{\dfrac{55 + 59}{2} = 57}

The class midpoint of 60 - 64 is \mathbf{\dfrac{60 + 64}{2} = 62}

Now, the table can be represented as:

Low-temperature             Frequency          x  

40 - 44                                    2                   42

45 - 49                                    5                   47

50 - 54                                    9                   52

55 - 59                                    6                   57

60 - 64                                    3                   62

The mean can now be determined as follows:

\mathbf{\bar x = \dfrac{\sum fx}{\sum f }}

\mathbf{\bar x = \dfrac{(2 \times 42)+ (5 \times 47) + ( 9\times 52) +(6\times 57) + (3 \times 62)}{2 + 5 + 9 + 6 + 3 }}

\mathbf{\bar x = \dfrac{1315}{25}}

\mathbf{\bar x = 52.6}

Therefore, we can conclude that the mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F. is lesser than the actual mean of 57.6° F

Learn more about the mean of frequency distribution here:

brainly.com/question/12269435

3 0
2 years ago
Are this too answer correct
Ede4ka [16]
I believe so friend budddy
4 0
3 years ago
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