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4 years ago

Find the quotient. in 4/5 divide by 2/12

Mathematics

2 answers:

Alinara [238K]4 years ago

6 0

Answer:

4.80 or 4 4/5 is the answer

Step-by-step explanation:

PtichkaEL [24]4 years ago

4 0

Answer:

4 4/5 my dood

Step-by-step explanation:

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3. On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the mid

Tju [1.3M]

Answer:

Step-by-step explanation:

im 50% sure this write dont blame me man

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3 years ago

3x3 – 19x2 + kx – 30 What is the value of k?

Citrus2011 [14]

Answer:

Let's simplify step-by-step.

(3)(3)−(19)(2)+kx−30

=9+−38+kx+−30

Combine Like Terms:

=9+−38+kx+−30

=(kx)+(9+−38+−30)

=kx+−59

Answer:

=kx−59

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3 years ago

Find the volume of the prism.

Gemiola [76]

Answer:

Step-by-step explanation:

The volume of the triangular prism, this is an isosceles triangular prism is

V=1/2 * a*b*h

V=1/2 x10x8x14=560 cm^3

4 0

3 years ago

Plz show work if needed

Cerrena [4.2K]

It is C a pyramid! They ask for shape but no measurements

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3 years ago

Read 2 more answers

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$