Question

Solve for the value of z :5(z+4)+5(2-z)​

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's evaluate ~

$\qquad \sf \dashrightarrow \: 5(z + 4) + 5(2 - z)$

$\qquad \sf \dashrightarrow \: (5 \cdot z) + (5\cdot4) + (5\cdot2) - (5\cdot z)$

$\qquad \sf \dashrightarrow \: 5z + 20 + 10 - 5z$

$\qquad \sf \dashrightarrow \: 5z - 5z+ 20 + 10$

$\qquad \sf \dashrightarrow \: 30$

So, the equivalent expression is 30

Answer 2

Answer:

30

Step-by-step explanation:

Let us divide the whole expression by 5. Then we must multiply the whole expression by 5 to obtain the same value as before.

Thus, we get the following expression:

$\implies\huge\text{[}\dfrac{5(z+4)+5(2-z)}{5}\huge\text{]} \times 5$

$\implies\huge\text{[}\dfrac{(z+4)+(2-z)}{1}\huge\text{]} \times 5$

Now, open the inner-most parentheses as the expression inside the inner-most parentheses, cannot be simplified further.

$\implies\huge\text{[}\dfrac{z+4+2-z}{1}\huge\text{]} \times 5$

It should be noted that any number being subtracted from the same number is equivalent to 0. Therefore, we get the following expression:

$\implies\huge\text{[}\dfrac{4+2}{1}\huge\text{]} \times 5$

Simplify the expression inside the long brackets.

$\implies\huge\text{[}\dfrac{6}{1}\huge\text{]} \times 5$

Now, we can open the long brackets and simplify the product of 6/1 and 5.

$\implies\huge\text{[}\dfrac{6}{1}\huge\text{]} \times 5 = \dfrac{6 \times 5}{1} = \dfrac{30}{1} = 30$

Therefore, the simplified expression is 30.

Learn more about one-variable expressions: brainly.com/question/27721172