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2 years ago

Triangle ABC has vertices A(0, 2), B(x, 0), and C(0, -2). Determine the value of x that makes triangle ABC a regular triangle.

Mathematics

1 answer:

Jobisdone [24]2 years ago

5 0

Answer:

$x = \sqrt{12 } = 2 \sqrt{3} \: or \\ x = - \sqrt{12} = - 2 \sqrt{3}$

Step-by-step explanation:

In order for the triangle to be a right one we need every side to be of the same length. see the photo for furyher explanation.

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6x^4 • 5x^3<br><br> Pleas help<br> Me on this problem!!

Leto [7]

30x^7

Multiply the coefficients (6•5) to get 30, then add the exponents (4+3) to get 7

Hope this helps!

4 0

3 years ago

Solving equations and distributive property

Tomtit [17]

Answer:

x=20

Step-by-step explanation:

2(x+10)=60

distribute 2 by multiplying numbers in parenthesis

2x+20=60

subtract 20 from both sides

2x=40

divide both sides by 2

----------

x=20

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4 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

5x + 10 > 35<br> How do you work this out?

Alexxx [7]

Answer:

$x > 5$

Step-by -step explanation:

Solving inequalities is similar to solving equations.

$5x + 10 > 35$

Subtract 10 from both sides.

$5x > 25$

Divide by 5 from both sides to isolate the x.

$x > 5$

3 0

2 years ago

Read 2 more answers

ABC company manufactures pesticides. The company has used a bright packaging color to distinguish it from other brands. The comp

Bad White [126]

Answer:

It is B or C

Step-by-step explanation:

4 0

2 years ago