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MatroZZZ [7]
3 years ago
9

Triangle ABC has vertices A(0, 2), B(x, 0), and C(0, -2). Determine the value of x that makes triangle ABC a regular triangle.

Mathematics
1 answer:
Jobisdone [24]3 years ago
5 0

Answer:

x =  \sqrt{12 }  = 2 \sqrt{3}  \: or \\ x =   -  \sqrt{12}  =  - 2 \sqrt{3}

Step-by-step explanation:

In order for the triangle to be a right one we need every side to be of the same length. see the photo for furyher explanation.

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Use the figure below to determine the length of side x. Question 3 options: x = 6 x = 12√3 x = 4√3 x = 6√2
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3 years ago
Solve the following initial-value problem:<br><br> (ex+y)dx+(3+x+yey)dy=0, y(0)=1<br><br> 0=
alex41 [277]

Answer:

e^x+xy+3y+(y-1)e^y=4

Step-by-step explanation:

Given that

(e^x+y)dx+(3+x+ye^y)dy=0

Here

M=e^x+y

N=3+x+ye^y

We know that

M dx + N dy=0 will be exact if

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}

So

\frac{\partial M}{\partial y}=1

\frac{\partial N}{\partial x}=1

it means that this is a exact equation.

\int d\left(e^x+xy+3y+(y-1)e^y\right)=0

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Given that

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So the our final equation will be

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3 0
3 years ago
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