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choli [55]
2 years ago
11

a student walks 8 steps east 6 steps northeast 9 steps north west what is her displacement? include magnitude and direction

Mathematics
1 answer:
kati45 [8]2 years ago
8 0

The displacement is 18.03 steps, and the direction is 47.25°

<h3>How to get the displacement?</h3>

We know that displacement is the difference between the final position and the initial position.

We assume the initial position (0, 0). Let's define the positive x-axis as the east and the positive y-axis as the north.

First, the student moves 8 steps east, so she is at:

(0 + 8, 0)

Then she moves 6 steps northeast, so the new position is:

(6*cos(45°) + 8,  6*cos(45°))

Finally, she moves 9 steps due north, so we have:

(6*cos(45°) + 8,  6*cos(45°) + 9)

Then the final position is:

(12.24, 13.24)

So the displacement is:

D = (12.24, 13.24) - (0, 0) =  (12.24, 13.24)

The magnitude of the displacement is:

|D| = \sqrt{12.24^2 + 13.24^2} = 18.03

So the magnitude is 18.03 steps.

And the direction is given by the arctangent of the quotient between the y-component and the x-component:

\theta = Arctg(13.24/12.24) = 47.25 \°

If you want to learn more about displacements:

brainly.com/question/4931057

#SPJ1

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