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luda_lava [24]
3 years ago
8

Enter the slope of the line through the points (5, 2) and (-3, -7).

Mathematics
1 answer:
ehidna [41]3 years ago
3 0

Answer:

m=9/8 or 1 1/8

Step-by-step explanation:

m= change in y over change in x

2 - -7 = 9

5 - -3 = 8

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An engineer is going to redesign an ejection seat for an airplane. the seat was designed for pilots weighing between 130lb and 1
Vlad [161]

Answer: 0.4758

Step-by-step explanation:

Given : Mean : \mu=137\text{ lb}

Standard deviation : \sigma =28.9\text{ lb}

Also, the new population of pilots has normally distributed .

The formula to calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x=130 lb .

z=\dfrac{130-137}{28.9}=-0.2422145\approx-0.24

For x=171lb.

z=\dfrac{171-137}{28.9}=1.1764705\approx1.18

The p-value =P(-0.24

=0.8809999-0.4051651=0.4758348\approx0.4758348\approx0.4758

Hence, the required probability : 0.4758

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3 years ago
The toy shop is located at (-2, 3) and the ice skating rink is located at (-2, -5). Plot these points on the coordinate grid. If
natta225 [31]

Answer:

8 miles

Step-by-step explanation:

We start by calculating the distance between the two points

To calculate this, we use the distance formula

Let the distance be D

We have the formula as;

D = √(x2-x1)^2 + (y2-y1)^2

D = √(-2+2)^2 + (-5-3)^2

D = √(64)

D = 8 units

Since 1 unit is 1 mile,

then 8 units will be 8 * 1 = 8 miles

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Leto [7]

Answer:

45

Step-by-step explanation:

73+62=135

180-135=45

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I need help ASAPPPPPPP!
telo118 [61]

Answer: The first box

Step-by-step explanation:

V represents volume and r represents radius

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The Identity function i behaves just like the number 1. That is (F o i)=f and (i o g)= g
andrezito [222]

I'll denote the identity function by \mathrm{Id}. Then for any functions f with inverse f^{-1},

\begin{cases}f\circ\mathrm{Id}=f\\\mathrm{Id}\circ f=f\\f\circ f^{-1}=\mathrm{Id}\end{cases}

One important fact is that composition is associative, meaning for functions f,g,h, we have

(f\circ g)\circ h=f\circ(g\circ h)

So given

h=f\circ g

we can compose the functions on either side with g^{-1}:

h\circ g^{-1}=(f\circ g)\circ g^{-1}=f\circ(g\circ g^{-1})

then apply the rules listed above:

h\circ g^{-1}=f\circ\mathrm{Id}=f

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