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Anika [276]
2 years ago
6

Can someone do this for me please?! Just the answer pls

Mathematics
1 answer:
Lana71 [14]2 years ago
6 0
<h2>For the number 1<u>.</u><u>.</u></h2>

<h2><u>angle </u><u>at </u><u>center </u><u>=</u><u> </u><u>2</u><u>×</u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>at </u><u>circumference</u></h2><h2><u>the </u><u>angle </u><u>at </u><u>center </u><u>(</u><u>o)</u><u> </u><u>is </u><u>equal</u><u> </u><u>to</u><u> </u><u>1</u><u>4</u><u>1</u></h2>

<u>therefore:</u>

<h2><u>1</u><u>4</u><u>1</u><u> </u><u>=</u><u> </u><u>2</u><u>x</u></h2><h2><u>divide</u><u> </u><u>both </u><u>sides </u><u>by </u><u>2</u></h2><h2><u>x </u><u>=</u><u> </u><u>7</u><u>0</u><u>.</u><u>5</u></h2>

<u>option</u><u> </u><u>(</u><u>A)</u><u>.</u>

<u>(</u><u> </u><u>the </u><u>number </u><u>2</u><u> </u><u>and </u><u>3</u><u> </u><u>questions</u><u> </u><u>aren't</u><u> </u><u>correct </u><u>)</u>

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Hey!
So the number between needs to be the same number away from 23 and 49. 18 is less than 23 and 49 but we need a number between 23 and 49, so thats a no. same with 72.
Now we are left with 36 and 29.5.
well 29.5 is 6.5 points away from 23 but it is 19.5 points away from 49. So thats a no too because the difference is not the same.
now 36 is 13 away from 23 and also 13 away from 49 and the difference is the same 
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