Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
General equation: y = mx + c
where m is the slope.
So if there’s a negative sign on mx, it is a negative slope and vice versa.
The x in y = mx + b represents the input, C.
Distribute Property 5(x+6) basically means 5×x + 5×6 = 5x+30
37= -3+5x+30 (subtract 30 on both sides)
7=-3+5x (add three on both sides)
10= 5x (divide 5 on both sides)
x=2
Answer:
50 degrees
Step-by-step explanation:
PLZ MARK BRAINLIEST
