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insens350 [35]
3 years ago
9

Need help with this math question

Mathematics
1 answer:
Yanka [14]3 years ago
5 0

Answer:

scale factor

Step-by-step explanation:

A vocabulary term is what it is. Often, there is no explanation.

To change (multiply by a constant) every dimension of a figure is to scale it; the number by which it is scaled is a <em>scale factor</em>.

<em>Area</em> and <em>Volume</em> are parameters of a figure. <em>Enlargement</em> is the process or the result of the process of making things larger (generally). The enlargment may actually be a reduction if the scale factor is less than 1.

A <em>coefficient</em> is the multiplier of some variable or variable term. It is often a constant, but may not be. An equation involving figure dimensions may use a scale factor as a coefficient, but in general, the terms are unrelated.

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Nady [450]

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Step-by-step explanation:

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3 years ago
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

x^2-3x=x(x-3)

The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

7 0
3 years ago
Janet plans to save $22.50 each week until she has enough to buy a $180 bicycle. After how many weeks will she have enough money
Darya [45]

Answer:

Step-by-step explanation:

8weeeks bc 22.50*8=180

4 0
2 years ago
What is 9/8 in simplest from
Alchen [17]
9/8 is in the simplest form
3 0
4 years ago
(n + 12) x 5 + 7n Need equivalent expression
astraxan [27]

Answer:

12n + 60

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

(n + 12) × 5 + 7n

<u>Step 2: Simplify</u>

  1. Distribute 5:                     5(n) + 5(12) + 7n
  2. Multiply:                            5n + 60 + 7n
  3. Combine like terms:        12n + 60
6 0
3 years ago
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