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4 years ago

If u +t=5 and u – t = 2, what is the value of (u – t)(u2 – ť)? ?

Mathematics

1 answer:

raketka [301]4 years ago

5 0

Answer:

The Heaviside step function, or the unit step function, usually denoted by H or θ (but sometimes u, 1 or ), is a discontinuous function, named after Oliver Heaviside (1850–1925), whose value is zero for negative arguments and one for positive arguments.

Step-by-step explanation:

L at time ť will meet at the point z " given by the equations : z " = - ( c + U ) t ... + B ) t = ť + t " = 2y - t = tı ( 93 ) Therefore , we do not recover the value 2t = 2L / c ... if the extinction time is not zero in equation 92 , one can verify the equality t ' + t ... the mirror located on the arm covers the distance Ut ' during the time t

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Evaluate j(5+k) + 15, when j=3 and k=4

maksim [4K]

Answer:

Step-by-step explanation:

j(5+k) + 15

Let j = 3 and k = 4

3(5+4) + 15

Parentheses first

3 (9) +15

Multiply

27 + 15

Add

6 0

3 years ago

Read 2 more answers

X^4 -5x^2= 3x^2 +48 solve by factoring! and simplify all irrational and complex solutions.

Katen [24]

Answer:

2√(3) or -2√(3) or 2i or -2i

Step-by-step explanation:

All the steps are in the photo I attached

(I forgot about negative side, sorry)

5 0

3 years ago

Please help me I would really like to know

Fittoniya [83]

The correct answer is 6x-15

3 0

3 years ago

Read 2 more answers

Renee scores an average of 153 points in a game of bowling, and her points in a game of bowling are normally distributed. Suppos

Lelu [443]

Answer:

$\sigma=\frac{175-153}{2}=11$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent points in a game of bowling of a population, and for this case we know the distribution for X is given by:

$X \sim N(153,unknown)$

Where $\mu=153$ and $\sigma=?$

We know that the value for Renee is X=175 and the z score obteined was Z=2.

Solution to the problem

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{X-\mu}{\sigma}$

We are interested on the value of $\sigma$ and we can solv for it:

$z \sigma = X-\mu$

$\sigma=\frac{X-\mu}{z}$

And replacing the values we have:

$\sigma=\frac{175-153}{2}=11$

5 0

3 years ago

Read 2 more answers

Convert the decimal number 183 into an equivalent 32 bit binary number. show all your work.

german

The bits are determined by repeated division by 2 to yield either 0 or 1.

183/2 = 91 rem 1 => 1 (lowest bit) 2⁰
91/2 = 45 rem 1 => 1 (next higher bit) 2¹
45/2 = 22 rem 1 => 1 (next higher bit) 2²
22/2 = 11 rem 0 => 0 (next highrt bit) 2³
11/2 = 5 rem 1 => 1 (next higher bit) 2⁴
5/2 = 2 rem 1 => 1 (next higher bit) 2⁵
2/2 = 1 rem 0 => 0 (next higher bit) 2⁶
1/2 = 0 rem 1 => 1 (next higher bit) 2⁷
The next higher 24 bits have 0 in each bit.

For 32-bit system,
183 = 00000000 00000000 00000000 10110111 (with a space between bytes for readability)

Answer: 00000000000000000000000010110111

7 0

4 years ago