What is the equation of the line, in point-slope form, that goes through (-2,-1) and is perpendicular to y=5x+3?
1 answer:
The correct answer is B. y + 1 = -1/5 (x + 2)
I got B by putting the numbers in point-slope form which is y - y1 = m ( x - x1 ) so I got: y + 1 = m ( x + 2 )
Then to find m(the slope) I knew if the slope was 5 it would be parallel to y=5x+3 so therefore -1/5 would be perpendicular to the line y=5x=3.
Hope that helps!!
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17) The answer is option B. 273.8 m^2
16) The answer is option A. 2.9887
Step-by-step explanation:
15+15+15=45 Hope this helps.
Use the slope formula (y2-y1)/(x2-x1)
(0+9)/(4+7)=9/11
Since q is parallel to r the slope will be the same. 9/11 is the slope of line r
I think that would be 650
