Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755
Step-by-step explanation:
Given that,
Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74
Random sample of freshman, n = 81
Utilizing central limit theorem,

So,

= P( Z > 0.0616)
= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.
Changed both of them to a fraction
Answer: 30,000
Step-by-step explanation:
Round 5 up to 10 25000 to 30000
<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>
I believe the answer is AD=7.0