11 is divisible by three three times with a remainder of two so the mixed number would be 3 2/3<span />
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
I got you  first you want to get some little ceasers 
 
        
             
        
        
        
<span>Using whole numbers, fractions, and decimals, these are the eight addition equations that have the sum of 10
</span>1. 5+5=10
2. 1 1/2 + 8 1/2 =10
3. 2.9+7.1=10
4. 6 1/3 + 3 2/3 =10
5. 4 3/5 + 5 2/5=10
6. 9.01+.99=10
7. 3.72+6.28 = 10
8.  8 8/9+ 1 1/9=10
        
             
        
        
        
By either long or synthetic division, it's easy to show that

The quartic will be exactly divisible by 

 when the numerator of the remainder term vanishes, or for those values of 

 such that

I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.